Question
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Solve the quadratic equation by completing the square. \[ x^{2}-14 x+35=0 \] First, choose the appropriate form and fill in the blanks with the correct numbers. Then, solve the equation. Simplify your answer as much as possible. If there is more than one solution, separate them with commas. Form: Solution: \( (x-\square)^{2} \)

Ask by Guerrero Kelley. in the United States
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\( x = 7 - \sqrt{14}, \) \( x = 7 + \sqrt{14} \)

Solution

Solve the equation \( x^{2}-14x+35=0 \). Solve the quadratic equation by following steps: - step0: Solve using the quadratic formula: \(x^{2}-14x+35=0\) - step1: Solve using the quadratic formula: \(x=\frac{14\pm \sqrt{\left(-14\right)^{2}-4\times 35}}{2}\) - step2: Simplify the expression: \(x=\frac{14\pm \sqrt{56}}{2}\) - step3: Simplify the expression: \(x=\frac{14\pm 2\sqrt{14}}{2}\) - step4: Separate into possible cases: \(\begin{align}&x=\frac{14+2\sqrt{14}}{2}\\&x=\frac{14-2\sqrt{14}}{2}\end{align}\) - step5: Simplify the expression: \(\begin{align}&x=7+\sqrt{14}\\&x=\frac{14-2\sqrt{14}}{2}\end{align}\) - step6: Simplify the expression: \(\begin{align}&x=7+\sqrt{14}\\&x=7-\sqrt{14}\end{align}\) - step7: Rewrite: \(x_{1}=7-\sqrt{14},x_{2}=7+\sqrt{14}\) The solutions to the quadratic equation \(x^{2}-14x+35=0\) by completing the square are \(x_{1}=7-\sqrt{14}\) and \(x_{2}=7+\sqrt{14}\).

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Bonus Knowledge

To complete the square for the equation \(x^{2} - 14x + 35 = 0\), we first need to adjust it into a perfect square format. First, we can take the coefficient of \(x\) which is \(-14\), halve it to get \(-7\), and then square it to find \(49\). We rewrite the equation as \(x^{2} - 14x + 49 - 49 + 35 = 0\), or \(x^{2} - 14x + 49 = 14\). This allows us to write it as: \( (x - 7)^{2} = 14 \). Now, let's solve for \(x\). Taking the square root of both sides gives us: \( x - 7 = \pm \sqrt{14} \). From this, we can isolate \(x\): \( x = 7 \pm \sqrt{14} \). So, the solutions to the equation are: Solution: \( 7 + \sqrt{14}, 7 - \sqrt{14} \).

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