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Triangle ABC is an isosceles right triangle. What is the measure of one base angle? \( 30^{\circ} \) \( 45^{\circ} \) \( 60^{\circ} \) \( 90^{\circ} \)

Ask by Peterson Bright. in the United States
Jan 24,2025

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Answer

Each base angle is \(45^{\circ}\).

Solution

In an **isosceles right triangle**, two sides are equal in length, and one of the angles is a right angle (\(90^{\circ}\)). Here's how to determine the measure of the base angles: 1. **Sum of Angles**: The sum of all angles in any triangle is \(180^{\circ}\). 2. **Right Angle**: One angle is \(90^{\circ}\). 3. **Remaining Angles**: The remaining two angles are equal since the triangle is isosceles. Let each base angle be \(x\). Then: \[ 90^{\circ} + x + x = 180^{\circ} \] \[ 2x = 90^{\circ} \] \[ x = 45^{\circ} \] **Answer:** \(45^{\circ}\) **Option:** \( \boxed{45^{\circ}} \)

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In an isosceles right triangle, the two base angles are equal, and the sum of all angles in any triangle is \( 180^{\circ} \). Therefore, if we let each of the base angles be \( x \), we can express this as: \( x + x + 90^{\circ} = 180^{\circ} \). Solving for \( x \) gives us \( x = 45^{\circ} \). So, the measure of each base angle in triangle ABC is \( 45^{\circ} \). Triangles like this are foundational in trigonometry and geometry. The \( 45-45-90 \) triangle has special properties; the lengths of the legs are equal, and the hypotenuse can be found using the formula \( h = l\sqrt{2} \), where \( l \) is the length of a leg. This is a useful relationship when solving real-world problems involving slopes or diagonal cuts!

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