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CEOMEUR2. A regular octagonal pyramid has a base with side length 13 inches and a slant height of 20 inches. What is the lateral surface area?

Ask by Reid Matthews. in the United States
Jan 24,2025

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Answer

The lateral surface area of the regular octagonal pyramid is 1,040 square inches.

Solution

To find the lateral surface area of a regular octagonal pyramid, follow these steps: 1. **Determine the Number of Lateral Faces:** - A regular octagonal pyramid has 8 triangular lateral faces. 2. **Find the Perimeter of the Base:** - The base is a regular octagon with each side measuring 13 inches. - **Perimeter** = Number of sides × Side length = \(8 \times 13 = 104\) inches. 3. **Use the Formula for Lateral Surface Area (LSA):** \[ \text{LSA} = \frac{\text{Perimeter} \times \text{Slant Height}}{2} \] - **Slant Height** = 20 inches. \[ \text{LSA} = \frac{104 \times 20}{2} = \frac{2080}{2} = 1040 \text{ square inches} \] **Final Answer:** The lateral surface area is 1,040 square inches.

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To calculate the lateral surface area of a regular octagonal pyramid, you first find the area of one of the triangular faces and then multiply it by the number of faces (which is 8 for an octagonal pyramid). The area \(A\) of each triangular face can be calculated using the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{slant height} \] The base of each triangular face is the side of the octagon, which is 13 inches, and the slant height is 20 inches. So, \[ A = \frac{1}{2} \times 13 \times 20 = 130 \text{ square inches} \] Since there are 8 triangular faces, the total lateral surface area is: \[ \text{Lateral Surface Area} = 8 \times 130 = 1040 \text{ square inches} \] So, the lateral surface area of the pyramid is 1040 square inches.

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