Use a calculator to evaluate the expression.

(Do not round until the final answer. Then round to three decimal places as needed.)

Ask by Schmidt Delgado. in the United States

Mar 26,2025

Question

Use a calculator to evaluate the expression.

(Do not round until the final answer. Then round to three decimal places as needed.)

Ask by Schmidt Delgado. in the United States

Mar 26,2025

UpStudy AI · Accepted Answer

Calculate or simplify the expression $$ \frac{2 \ln 8+\log 16}{\log 121-\ln 11} $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{2\ln{\left(8ight)}+\log_{10}{\left(16ight)}}{\log_{10}{\left(121ight)}-\ln{\left(11ight)}}$$
- step1: Add the numbers:
  $$\frac{2	imes 3\ln{\left(2ight)}+4\log_{10}{\left(2ight)}}{\log_{10}{\left(121ight)}-\ln{\left(11ight)}}$$
- step2: Simplify:
  $$\frac{2	imes 3\ln{\left(2ight)}+4\log_{10}{\left(2ight)}}{2\log_{10}{\left(11ight)}-\ln{\left(11ight)}}$$
- step3: Expand the expression:
  $$\frac{6\ln{\left(2ight)}+4\log_{10}{\left(2ight)}}{2\log_{10}{\left(11ight)}-\ln{\left(11ight)}}$$
The expression $$\frac{2 \ln 8+\log 16}{\log 121-\ln 11}$$ is approximately equal to $$-17.019469$$. Rounding to three decimal places, the final answer is $$-17.019$$.
The expression $$\frac{2 \ln 8+\log 16}{\log 121-\ln 11}$$ is approximately $$-17.019$$.

Use a calculator to evaluate the expression.

(Do not round until the final answer. Then round to three decimal places as needed.)

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Use a calculator to evaluate the expression. (Do not round until the final answer. Then round to three decimal places as needed.)

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Use a calculator to evaluate the expression.

(Do not round until the final answer. Then round to three decimal places as needed.)