Calculate the mass $$ \% $$ of Na in sodium dihydrogen phosphate heptahydrate. $$ \% \% \mathrm{Na} $$

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To calculate the mass percentage of sodium (Na) in sodium dihydrogen phosphate heptahydrate ($$\text{NaH}_2\text{PO}_4 \cdot 7\text{H}_2\text{O}$$), follow these steps:

### 1. Determine the Molecular Formula
The molecular formula is:
$$
\text{NaH}_2\text{PO}_4 \cdot 7\text{H}_2\text{O}
$$

### 2. Calculate the Molar Mass of Each Component

- **Sodium (Na):**  
  $$
  1 \times 22.99 \, \text{g/mol} = 22.99 \, \text{g/mol}
  $$

- **Hydrogen (H):**  
  - From $$\text{H}_2\text{PO}_4$$: $$2 \times 1.008 \, \text{g/mol} = 2.016 \, \text{g/mol}$$
  - From $$7\text{H}_2\text{O}$$: $$7 \times (2 \times 1.008) \, \text{g/mol} = 14.112 \, \text{g/mol}$$
  - **Total Hydrogen:**  
    $$
    2.016 \, \text{g/mol} + 14.112 \, \text{g/mol} = 16.128 \, \text{g/mol}
    $$

- **Phosphorus (P):**  
  $$
  1 \times 30.97 \, \text{g/mol} = 30.97 \, \text{g/mol}
  $$

- **Oxygen (O):**  
  - From $$\text{H}_2\text{PO}_4$$: $$4 \times 16.00 \, \text{g/mol} = 64.00 \, \text{g/mol}$$
  - From $$7\text{H}_2\text{O}$$: $$7 \times 16.00 \, \text{g/mol} = 112.00 \, \text{g/mol}$$
  - **Total Oxygen:**  
    $$
    64.00 \, \text{g/mol} + 112.00 \, \text{g/mol} = 176.00 \, \text{g/mol}
    $$

### 3. Calculate the Total Molar Mass
$$
\text{Total Molar Mass} = 22.99 \, (\text{Na}) + 16.128 \, (\text{H}) + 30.97 \, (\text{P}) + 176.00 \, (\text{O}) = 246.088 \, \text{g/mol}
$$

### 4. Determine the Mass Percentage of Sodium (Na)
$$
\%\text{Na} = \left( \frac{22.99 \, \text{g/mol}}{246.088 \, \text{g/mol}} \right) \times 100\% \approx 9.35\%
$$

### **Final Answer**
The mass percent of sodium ($$\text{Na}$$) in sodium dihydrogen phosphate heptahydrate is approximately **9.35 %**.
The mass percentage of sodium (Na) in sodium dihydrogen phosphate heptahydrate is approximately **9.35%**.

Calculate the mass of Na in sodium dihydrogen phosphate heptahydrate.

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