Find the slope and the $$ y $$-intercept of the line. $$ y=\frac{1}{4} x $$ slope: $$ y $$-intercept: $$ \square $$

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To determine the slope and the $$ y $$-intercept of the line given by the equation:

$$
y = \frac{1}{4}x
$$

we can compare it to the slope-intercept form of a linear equation:

$$
y = mx + b
$$

where:
- $$ m $$ is the **slope** of the line.
- $$ b $$ is the **$$ y $$-intercept**, the point where the line crosses the $$ y $$-axis.

**1. Finding the Slope ($$ m $$):**

In the equation $$ y = \frac{1}{4}x $$, the coefficient of $$ x $$ is $$ \frac{1}{4} $$. This coefficient represents the slope of the line.

$$
\text{slope} = \frac{1}{4}
$$

**2. Finding the $$ y $$-Intercept ($$ b $$):**

The equation can be rewritten to explicitly show the $$ y $$-intercept by comparing it to the slope-intercept form:

$$
y = \frac{1}{4}x + 0
$$

Here, the constant term is $$ 0 $$, which means the line crosses the $$ y $$-axis at the origin.

$$
y\text{-intercept} = 0
$$

**Final Answer:**

$$
\boxed{
\begin{aligned}
\text{slope: } & \frac{1}{4} \
y\text{-intercept: } & 0
\end{aligned}
}
$$
The slope is $$ \frac{1}{4} $$ and the $$ y $$-intercept is $$ 0 $$.

Find the slope and the \( y \)-intercept of the line. \( y=\frac{1}{4} x \) slope: \( y \)-intercept: \( \square \)

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