A coordinate system with the following attributes: - Three points are plotted at \( (-4,5),(4,1) \), and \( (8,-1) \). - A straight line extends through the points. Which ordered pair would also be on the line shown?

To find an ordered pair that also lies on the line created by the points \((-4,5)\), \((4,1)\), and \((8,-1)\), we first need to determine the slope of the line. The slope between the first two points can be calculated as: \[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{4 - (-4)} = \frac{-4}{8} = -\frac{1}{2} \] Using the point-slope form equation of a line, we can take one of the points, say \((4,1)\): \[ y - 1 = -\frac{1}{2}(x - 4) \] This simplifies to: \[ y = -\frac{1}{2}x + 3 \] Now, we can pick a value for \(x\) and find the corresponding \(y\). If we choose \(x = 0\): \[ y = -\frac{1}{2}(0) + 3 = 3 \] Thus, the ordered pair \((0, 3)\) is also on the line!