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A data set consist of the following 6 values: The range is 6 . The median is 5 . The lower quartile is 4 . The interquartile range is 3 . Given that \( x
Ask by Lawson Bernard. in Singapore
Jan 22,2025

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Answer

\( x = 2 \), \( y = 7 \), and \( z = 8 \).

Solution

To determine the values of \( x \), \( y \), and \( z \) in the data set, let's analyze the given information step by step. ### Given: - **Number of values in the data set:** 6 - **Range:** 6 - **Median:** 5 - **Lower Quartile (Q1):** 4 - **Interquartile Range (IQR):** 3 - **Relation:** \( x < y < z \) ### Step 1: Arrange the Data Set Let’s denote the ordered data set as: \[ v_1, v_2, v_3, v_4, v_5, v_6 \] where \( v_1 \leq v_2 \leq v_3 \leq v_4 \leq v_5 \leq v_6 \). ### Step 2: Apply the Given Conditions 1. **Median:** - For 6 values, the median is the average of the 3rd and 4th values. \[ \frac{v_3 + v_4}{2} = 5 \implies v_3 + v_4 = 10 \] 2. **Lower Quartile (Q1):** - Q1 is the median of the first three values: \( v_1, v_2, v_3 \). \[ Q1 = v_2 = 4 \] 3. **Interquartile Range (IQR):** - IQR is the difference between the upper quartile (Q3) and Q1. \[ Q3 - Q1 = 3 \implies Q3 = 7 \] - Q3 is the median of the last three values: \( v_4, v_5, v_6 \). \[ Q3 = v_5 = 7 \] 4. **Range:** \[ \text{Range} = v_6 - v_1 = 6 \implies v_6 = v_1 + 6 \] ### Step 3: Determine Possible Values From the above conditions: - \( v_2 = 4 \) - \( v_5 = 7 \) - \( v_3 + v_4 = 10 \) Possible integer pairs for \( (v_3, v_4) \) that satisfy \( v_3 \leq v_4 \leq 7 \): - \( (4, 6) \) Using this pair: - \( v_1 \leq 4 \) (since \( v_2 = 4 \)) - \( v_6 = v_1 + 6 \) - \( v_4 = 6 \) and \( v_5 = 7 \) Possible values of \( v_1 \) and \( v_6 \): 1. If \( v_1 = 2 \), then \( v_6 = 8 \) The data set becomes: \( 2, 4, 4, 6, 7, 8 \) ### Step 4: Identify \( x \), \( y \), and \( z \) From the condition \( x < y < z \), and based on the data set \( 2, 4, 4, 6, 7, 8 \): - \( x = 2 \) - \( y = 7 \) - \( z = 8 \) ### Conclusion The values satisfying all the given conditions are: \[ x = 2, \quad y = 7, \quad z = 8 \] **Final Answer:** \[ x = 2,\ y = 7,\ \text{and}\ z = 8 \]

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The Deep Dive

To solve for \( x, y, \) and \( z \) in the given data set with the specified characteristics, we can break down the information provided. 1. **Range is 6**: This means that \( z - x = 6 \). 2. **Median is 5**: With 6 values, the median will be the average of the 3rd and 4th values when they are arranged in order. Hence, the 3rd and 4th values must average to 5. 3. **Lower quartile (Q1) is 4**: This indicates that the first half of the data (the lower half) must have values such that the median of these values is 4, meaning the 2nd value is 4. 4. **Interquartile range (IQR) is 3**: IQR is calculated as the difference between Q3 (the upper quartile) and Q1. Since Q1 is 4, Q3 must be 7 (7 - 4 = 3). Now let's outline the values: - From Q1, we have the 2nd value as 4. - The 3rd and 4th values must average to 5, so we can have either (5, 5) or (4 and 6). To maximize our use of the range and adhere to increasing order, we can use the values around 5: let’s assume 5 and 5 as candidates for now. - Further, since \( z - x = 6 \), and assuming \( z \) is one of the higher values, we could determine that this influences extremes. Putting these points together, we can conclude: - The arrangement could tentatively be \( [x, 4, 5, 5, 7, z] \). - If we replace \( z \) with \( x + 6 \), then let's say \( x = 1 \). This leads to \( z = 7 \). Thus, the values to satisfy these conditions might be \( x = 1, y = 4, z = 7 \). Confirming: - The ordered set becomes \( [1, 4, 4, 5, 5, 7] \). - The range: \( 7 - 1 = 6 \) ✔ - The median: \( (4 + 5) / 2 = 4.5 \), adjustments needed. Instead, let’s choose \( x = 3, y = 4, z = 9 \): - The arrangement: \( [3, 4, 5, 6, 7, 9] \) Now range: \(9 - 3 = 6\) ✔ Final values: \( x = 3, y = 4, z = 9 \).

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