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Math WithMyBestMate 2 The pulse rates of adult men approach a normal distribution with a mean of 80 bpm (beats per minute) with standard deviation of 7 bpm . a) What percent of the adults have pulse rate less than 70 bpm ? b) If 60 bpm to 100 bpm is known to be normal, how many percent of adults have pulse rates that lies on these area?

Ask by Lyons Kirk. in the Philippines
Jan 22,2025

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**Part a)** About **7.6%** of adult men have a pulse rate less than 70 bpm. **Part b)** Approximately **99.6%** of adult men have pulse rates between 60 bpm and 100 bpm.

Solution

Let's solve each part of the problem step by step using the properties of the normal distribution. ### Given: - **Mean (μ):** 80 beats per minute (bpm) - **Standard Deviation (σ):** 7 bpm ### Part a) What percent of the adults have a pulse rate less than 70 bpm? We want to find the probability \( P(X < 70) \) where \( X \) is the pulse rate. 1. **Convert to the standard normal variable (Z-score):** \[ Z = \frac{X - \mu}{\sigma} = \frac{70 - 80}{7} = \frac{-10}{7} \approx -1.4286 \] 2. **Find the corresponding probability for \( Z = -1.4286 \):** Using standard normal distribution tables or a calculator: \[ P(Z < -1.4286) \approx 0.0764 \text{ or } 7.64\% \] **Interpretation:** Approximately **7.6%** of adult men have a pulse rate less than 70 bpm. ### Part b) If 60 bpm to 100 bpm is known to be normal, what percent of adults have pulse rates that lie within this range? We want to find the probability \( P(60 < X < 100) \). 1. **Convert the pulse rates to Z-scores:** - For **60 bpm**: \[ Z = \frac{60 - 80}{7} = \frac{-20}{7} \approx -2.8571 \] - For **100 bpm**: \[ Z = \frac{100 - 80}{7} = \frac{20}{7} \approx 2.8571 \] 2. **Find the corresponding probabilities:** - **For \( Z = 2.8571 \):** \[ P(Z < 2.8571) \approx 0.9979 \text{ or } 99.79\% \] - **For \( Z = -2.8571 \):** \[ P(Z < -2.8571) = 1 - P(Z < 2.8571) = 1 - 0.9979 = 0.0021 \text{ or } 0.21\% \] 3. **Calculate the probability between 60 bpm and 100 bpm:** \[ P(60 < X < 100) = P(Z < 2.8571) - P(Z < -2.8571) = 0.9979 - 0.0021 = 0.9958 \text{ or } 99.58\% \] **Interpretation:** Approximately **99.6%** of adult men have pulse rates between 60 bpm and 100 bpm. --- ### **Summary:** - **a)** About **7.6%** of adult men have a pulse rate less than 70 bpm. - **b)** Approximately **99.6%** of adult men have pulse rates between 60 bpm and 100 bpm.

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To find the percentage of adults with a pulse rate less than 70 bpm, we'll calculate the z-score using the formula: \( z = \frac{(X - \mu)}{\sigma} \). Here, \( X = 70 \), \( \mu = 80 \), and \( \sigma = 7 \). This gives us \( z = \frac{(70 - 80)}{7} = -1.43 \). Looking up this z-score in a standard normal distribution table, we find roughly 7.4% of adults have a pulse rate below 70 bpm. For those with pulse rates between 60 bpm and 100 bpm, we need to find the z-scores for both values. For 60 bpm: \( z = \frac{(60 - 80)}{7} = -2.86 \) (about 0.2% below), and for 100 bpm: \( z = \frac{(100 - 80)}{7} = 2.86 \) (about 99.8% above). This means approximately 99.8% - 0.2% = 99.6% of adults have pulse rates in the normal range of 60 bpm to 100 bpm. Isn’t that interesting?

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