Math WithMyBestMate 2 The pulse rates of adult men approach a normal distribution with a mean of 80 bpm (beats per minute) with standard deviation of 7 bpm . a) What percent of the adults have pulse rate less than 70 bpm ? b) If 60 bpm to 100 bpm is known to be normal, how many percent of adults have pulse rates that lies on these area?
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To find the percentage of adults with a pulse rate less than 70 bpm, we'll calculate the z-score using the formula: \( z = \frac{(X - \mu)}{\sigma} \). Here, \( X = 70 \), \( \mu = 80 \), and \( \sigma = 7 \). This gives us \( z = \frac{(70 - 80)}{7} = -1.43 \). Looking up this z-score in a standard normal distribution table, we find roughly 7.4% of adults have a pulse rate below 70 bpm. For those with pulse rates between 60 bpm and 100 bpm, we need to find the z-scores for both values. For 60 bpm: \( z = \frac{(60 - 80)}{7} = -2.86 \) (about 0.2% below), and for 100 bpm: \( z = \frac{(100 - 80)}{7} = 2.86 \) (about 99.8% above). This means approximately 99.8% - 0.2% = 99.6% of adults have pulse rates in the normal range of 60 bpm to 100 bpm. Isn’t that interesting?