Question
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IGP(TAGK AT HOWE) 1.) Given: \( 3 x+2 y=6 \) a.) Determine the \( x \) and \( y \)-intercapts b.) graph by atteast 5 IPaints table of value of \( x \) c.) Graph by slope intureept form \( y=m x t b \) d.) Graph by intercept form.

Ask by Bates Bowers. in the Philippines
Feb 03,2025

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Answer

To graph the equation \( 3x + 2y = 6 \), follow these steps: 1. **Find Intercepts:** - **\( x \)-Intercept:** \( (2, 0) \) - **\( y \)-Intercept:** \( (0, 3) \) 2. **Create a Table of Values:** | \( x \) | \( y \) | |---------|---------| | -2 | 6 | | -1 | 4.5 | | 0 | 3 | | 1 | 1.5 | | 2 | 0 | 3. **Graph Using Slope-Intercept Form (\( y = -\frac{3}{2}x + 3 \)):** - Plot \( (0, 3) \) and \( (2, 0) \), then draw a straight line through them. 4. **Graph Using Intercept Form (\( \frac{x}{2} + \frac{y}{3} = 1 \)):** - Plot \( (2, 0) \) and \( (0, 3) \), then draw a straight line through them. All methods result in the same straight line passing through the intercepts \( (2, 0) \) and \( (0, 3) \).

Solution

Sure, let's work through each part of the problem step by step. ### **Given Equation:** \[ 3x + 2y = 6 \] --- ### **a. Determine the \( x \)- and \( y \)-Intercepts** **1. \( x \)-Intercept:** - To find the \( x \)-intercept, set \( y = 0 \) and solve for \( x \). \[ 3x + 2(0) = 6 \\ 3x = 6 \\ x = 2 \] - **\( x \)-Intercept:** \( (2, 0) \) **2. \( y \)-Intercept:** - To find the \( y \)-intercept, set \( x = 0 \) and solve for \( y \). \[ 3(0) + 2y = 6 \\ 2y = 6 \\ y = 3 \] - **\( y \)-Intercept:** \( (0, 3) \) --- ### **b. Create a Table of Values Using at Least 5 Points** To graph the equation accurately, it's helpful to plot several points. We'll choose various \( x \)-values and solve for the corresponding \( y \)-values. **Given Equation:** \[ 3x + 2y = 6 \\ \Rightarrow 2y = 6 - 3x \\ \Rightarrow y = -\frac{3}{2}x + 3 \] **Table of Values:** | \( x \) | \( y \) Calculation | \( y \) Value | |---------|---------------------------------|---------------| | -2 | \( y = -\frac{3}{2}(-2) + 3 = 3 + 3 = 6 \) | 6 | | -1 | \( y = -\frac{3}{2}(-1) + 3 = 1.5 + 3 = 4.5 \) | 4.5 | | 0 | \( y = -\frac{3}{2}(0) + 3 = 0 + 3 = 3 \) | 3 | | 1 | \( y = -\frac{3}{2}(1) + 3 = -1.5 + 3 = 1.5 \) | 1.5 | | 2 | \( y = -\frac{3}{2}(2) + 3 = -3 + 3 = 0 \) | 0 | **Points to Plot:** - \((-2, 6)\) - \((-1, 4.5)\) - \((0, 3)\) - \((1, 1.5)\) - \((2, 0)\) --- ### **c. Graph Using Slope-Intercept Form \( y = mx + b \)** **Step 1: Convert to Slope-Intercept Form** \[ 3x + 2y = 6 \\ \Rightarrow 2y = -3x + 6 \\ \Rightarrow y = -\frac{3}{2}x + 3 \] - **Slope (\( m \))**: \( -\frac{3}{2} \) - **\( y \)-Intercept (\( b \))**: \( 3 \) **Step 2: Plot the Graph** 1. **Start at the \( y \)-intercept:** Plot the point \( (0, 3) \). 2. **Use the slope to find another point:** From \( (0, 3) \), move down 3 units and right 2 units to reach \( (2, 0) \). 3. **Draw the Line:** Connect the points with a straight line, extending in both directions. **Graph Representation:** ``` y | 6 | * 5 | 4 | * 3 | * 2 | 1 | * 0 |__________ x 0 1 2 ``` --- ### **d. Graph Using Intercept Form** **Intercept Form of a Line:** \[ \frac{x}{a} + \frac{y}{b} = 1 \] where \( a \) is the \( x \)-intercept and \( b \) is the \( y \)-intercept. **Given Equation:** \[ 3x + 2y = 6 \] **Convert to Intercept Form:** \[ \frac{3x}{6} + \frac{2y}{6} = 1 \\ \Rightarrow \frac{x}{2} + \frac{y}{3} = 1 \] - **\( x \)-Intercept (\( a \))**: \( 2 \) (from \( \frac{x}{2} \)) - **\( y \)-Intercept (\( b \))**: \( 3 \) (from \( \frac{y}{3} \)) **Step 1: Plot the Intercepts** - Plot \( (2, 0) \) and \( (0, 3) \). **Step 2: Draw the Line** - Connect the two intercepts with a straight line, extending in both directions. **Graph Representation:** ``` y | 6 | 5 | 4 | 3 | * 2 | 1 | 0 |*__________ x 0 1 2 ``` --- ### **Final Graph Combining All Methods** All three graphing methods should result in the same straight line passing through the points \( (2, 0) \) and \( (0, 3) \). Here's a simplified representation: ``` y | 6 | * 5 | 4 | * 3 | * 2 | 1 | * 0 |__________ x 0 1 2 ``` - **Key Points:** \((-2, 6)\), \((-1, 4.5)\), \((0, 3)\), \((1, 1.5)\), \((2, 0)\) - **Slope-Intercept Form:** \( y = -\frac{3}{2}x + 3 \) - **Intercept Form:** \( \frac{x}{2} + \frac{y}{3} = 1 \) All methods provide consistent ways to graph the equation \( 3x + 2y = 6 \).

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To find the x and y-intercepts of the equation \( 3x + 2y = 6 \), set \( y = 0 \) to find the x-intercept: \[ 3x + 2(0) = 6 \quad \Rightarrow \quad 3x = 6 \quad \Rightarrow \quad x = 2 \] Set \( x = 0 \) for the y-intercept: \[ 3(0) + 2y = 6 \quad \Rightarrow \quad 2y = 6 \quad \Rightarrow \quad y = 3 \] So, the x-intercept is \( (2, 0) \) and the y-intercept is \( (0, 3) \). Next, let’s create a table of values using at least 5 points. Substitute values of \( x \) into the equation to find corresponding \( y \) values: | \( x \) | \( y \) | |---------|------------------| | -1 | 4.5 | | 0 | 3 | | 1 | 2 | | 2 | 0 | | 3 | -1.5 | For slope-intercept form, rearrange the equation: \[ 2y = -3x + 6 \quad \Rightarrow \quad y = -\frac{3}{2}x + 3 \] Here, the slope \( m = -\frac{3}{2} \) and the y-intercept \( b = 3 \). Starting from point \( (0,3) \), you can move down 3 units and right 2 units to plot another point. Finally, in intercept form, the equation can be expressed as: \[ \frac{x}{2} + \frac{y}{3} = 1 \] You can plot this by marking the intercepts, (2,0) on the x-axis and (0,3) on the y-axis, and then drawing a line through these points.

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