Solve for \( x: 2 e^{x+1}-6=10 \) \( \begin{array}{lll}1.079 & \text { b. } & 3.079 \\ 2,979.958 & \text { d. } & 2,981.958\end{array} \)
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The Deep Dive
To solve the equation \( 2 e^{x+1}-6=10 \), we first isolate the exponential term: 1. Add 6 to both sides: \[ 2 e^{x+1} = 16 \] 2. Divide both sides by 2: \[ e^{x+1} = 8 \] 3. Now, take the natural logarithm of both sides: \[ x + 1 = \ln(8) \] 4. Finally, solve for \( x \): \[ x = \ln(8) - 1 \] Using the fact that \( \ln(8) = \ln(2^3) = 3 \ln(2) \), we can compute \( x \). Calculating \( \ln(2) \approx 0.6931 \), we get: \[ \ln(8) \approx 3 \times 0.6931 \approx 2.0793 \] Thus, \[ x \approx 2.0793 - 1 \approx 1.0793 \] The closest answer is \( 1.079 \).