Question
upstudy study bank question image url

16 Let \( (H) \) be the hyperbola representing the function defined by \( f(x)=\frac{m x-3}{3 x-m} \), where \( m \) is is a real parameter other than \( 3 .(D) \) is the line of equation \( y=-x+4 \). \( 1^{\circ} \) Find the coordinates of the center \( I \) of \( (H) \) and deduce the set of points \( I \) when \( m \) varies.

Ask by Mullins Pearson. in Lebanon
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

For each real number \( m \) not equal to 3, the center \( I \) of the hyperbola \( (H) \) is located at \( \left( \frac{m}{3}, \frac{m}{3} \right) \). As \( m \) changes, the center \( I \) moves along the line \( y = x \).

Solution

Sign in to Unlock Answers for Free!

A Learning Platform Trusted by Millions of Real Students and Teachers.

star-icon Unlock

Reviewed and approved by the UpStudy tutoring team

Bonus Knowledge

The hyperbola \( (H) \) is given by the function \( f(x) = \frac{mx - 3}{3x - m} \). To find the center of the hyperbola, we need to express it in the form of the standard hyperbola equation. The center of a hyperbola generally occurs at the average of its asymptotes. Firstly, we can determine the vertical and horizontal asymptotes of the hyperbola by finding the values of \( x \) and \( y \) where the function is undefined. The vertical asymptote occurs when the denominator is zero, so we set \( 3x - m = 0 \), giving us \( x = \frac{m}{3} \). For the horizontal asymptote, we investigate the behavior of \( f(x) \) as \( x \) approaches infinity. We can see that as \( x \rightarrow \infty \), the dominant terms in \( f(x) \) (which are \( mx \) in the numerator and \( 3x \) in the denominator) lead us to the horizontal asymptote \( y = \frac{m}{3} \). Thus, the center \( I \) of the hyperbola is located at the point \( \left( \frac{m}{3}, \frac{m}{3} \right) \). As \( m \) varies, this point traces the line \( y = x \) in the coordinate plane. Therefore, the set of points \( I \) when \( m \) varies is the line defined by \( y = x \), excluding the point where \( m = 3 \), which results in an indeterminate form. In conclusion, the coordinates of the center \( I \) are \( \left( \frac{m}{3}, \frac{m}{3} \right) \), and as \( m \) changes (except when \( m = 3 \)), \( I \) moves along the line \( y = x \).

Related Questions

Latest Pre Calculus Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy