Question
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implify the expression. Assume all variables are positiv \( \begin{array}{lll}\text { 3. } \sqrt[3]{27 q^{9}} & \text { 14. } \sqrt[5]{\frac{x^{10}}{y^{5}}} & \text { 15. } \frac{6 x y^{3 / 4}}{3 x^{1 / 2} y^{1 / 2}}\end{array} \)

Ask by Santiago Perkins. in the United States
Feb 03,2025

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Answer

1. \( \sqrt[3]{27q^9} = 3q^3 \) 2. \( \sqrt[5]{\frac{x^{10}}{y^{5}}} = \frac{x^2}{y} \) 3. \( \frac{6xy^{3/4}}{3x^{1/2}y^{1/2}} = 2\sqrt[4]{x^2y} \)

Solution

Calculate or simplify the expression \( \sqrt[3]{27q^9} \). Simplify the expression by following steps: - step0: Solution: \(\sqrt[3]{27q^{9}}\) - step1: Transform the expression: \(\sqrt[3]{\left(3q^{3}\right)^{3}}\) - step2: Simplify the root: \(3q^{3}\) Calculate or simplify the expression \( \sqrt[5]{\frac{x^{10}}{y^{5}}} \). Simplify the expression by following steps: - step0: Solution: \(\sqrt[5]{\frac{x^{10}}{y^{5}}}\) - step1: Use the properties of radicals: \(\frac{\sqrt[5]{x^{10}}}{\sqrt[5]{y^{5}}}\) - step2: Simplify the expression: \(\frac{x^{2}}{y}\) Calculate or simplify the expression \( \frac{6xy^{3/4}}{3x^{1/2}y^{1/2}} \). Simplify the expression by following steps: - step0: Solution: \(\frac{6xy^{\frac{3}{4}}}{3x^{\frac{1}{2}}y^{\frac{1}{2}}}\) - step1: Simplify the expression: \(\frac{6x^{1-\frac{1}{2}}y^{\frac{3}{4}}}{3y^{\frac{1}{2}}}\) - step2: Calculate: \(\frac{6x^{\frac{1}{2}}y^{\frac{3}{4}}}{3y^{\frac{1}{2}}}\) - step3: Simplify the expression: \(\frac{6x^{\frac{1}{2}}y^{\frac{3}{4}-\frac{1}{2}}}{3}\) - step4: Calculate: \(\frac{6x^{\frac{1}{2}}y^{\frac{1}{4}}}{3}\) - step5: Calculate: \(2x^{\frac{1}{2}}y^{\frac{1}{4}}\) - step6: Simplify: \(2\sqrt[4]{x^{2}y}\) 简化后的表达式分别为: 1. \( \sqrt[3]{27q^9} = 3q^3 \) 2. \( \sqrt[5]{\frac{x^{10}}{y^{5}}} = \frac{x^2}{y} \) 3. \( \frac{6xy^{3/4}}{3x^{1/2}y^{1/2}} = 2\sqrt[4]{x^2y} \)

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For the first expression, \( \sqrt[3]{27 q^{9}} \), we can simplify it by recognizing that \( 27 = 3^3 \), so \( \sqrt[3]{27} = 3 \). For \( q^{9} \), since the index of the root is 3, we take \( q^{9/3} = q^{3} \). Thus, the simplified expression is \( 3q^{3} \). Moving on to the second expression, \( \sqrt[5]{\frac{x^{10}}{y^{5}}} \), we can split it into two parts: \( \sqrt[5]{x^{10}} \) and \( \sqrt[5]{y^{5}} \). The first part simplifies to \( x^{10/5} = x^{2} \) and the second part simplifies to \( y^{5/5} = y^{1} \). Therefore, the expression simplifies to \( \frac{x^{2}}{y} \). Finally, for the third expression \( \frac{6 x y^{3/4}}{3 x^{1/2} y^{1/2}} \), we can simplify the coefficients to get \( \frac{6}{3} = 2 \). For the variable \( x \), \( \frac{x}{x^{1/2}} = x^{1/2} \). For \( y \), we apply the rule of exponents: \( \frac{y^{3/4}}{y^{1/2}} = y^{(3/4 - 2/4)} = y^{1/4} \). Thus, the final simplified expression is \( 2 x^{1/2} y^{1/4} \).

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