Compute. \[ \begin{array}{ll}5^{2}= & (-3)^{2}= \\ 2^{5}= & 3^{3}=\end{array} \]

First additional information: Let's dive into the calculations! For \(5^{2}\), you multiply 5 by itself, which gives you 25—so, \(5^{2}=25\). On the other hand, \((-3)^{2}\) also results in a positive number as squaring a negative makes it positive: \((-3) \times (-3) = 9\), hence \((-3)^{2}=9\). Second additional information: Now for the other two! \(2^{5}\) means multiplying 2 by itself five times: \(2 \times 2 \times 2 \times 2 \times 2 = 32\), so \(2^{5}=32\). Meanwhile, for \(3^{3}\), multiply 3 by itself three times: \(3 \times 3 \times 3 = 27\), thus \(3^{3}=27\). Math can be fun, right?