A purchaser paid $$ \$ 1,539,13 $$ for a computer system that originally cost 81,050 , If the markup was $$ 21 \% $$ of the $$ 81,539,13 $$ selling price, then what is the percent markup based on cost? (Round to the nearest tenth percent) select one: a a, $$ 26.6 \% $$ b, $$ 81.0 \% $$ c, $$ 79.7 \% $$ d. $$ 35.7 \% $$

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Let's break down the problem step by step to find the percent markup based on cost.

### Given:
1. **Selling Price (S):** \$1,539.13
2. **Original Cost (C):** \$81,050
3. **Markup Percentage:** 21% of the selling price

### Understanding the Markup:
- The markup is **21% of the selling price**. This can be expressed as:
  
  $$
  \text{Markup} = 0.21 \times S
  $$

### Relationship Between Selling Price and Cost:
- The selling price is the sum of the original cost and the markup:

$$
  S = C + \text{Markup}
  $$

- Substituting the markup expression:

$$
  S = C + 0.21 \times S
  $$

- Rearranging to solve for $$ S $$:

$$
  S - 0.21 \times S = C \
  0.79 \times S = C \
  S = \frac{C}{0.79}
  $$

### Calculating the Markup Based on Cost:
- Now, substitute $$ S $$ back into the markup equation:

$$
  \text{Markup} = 0.21 \times \frac{C}{0.79} \approx 0.2658 \times C
  $$

- To find the **percent markup based on cost**, multiply by 100:

$$
  \text{Percent Markup} \approx 26.6\%
  $$

### **Answer:**

**a. 26.6 %**
The percent markup based on cost is **26.6%**.

A purchaser paid for a computer system that originally cost 81,050 , If the
markup was of the selling price, then what is the percent markup based
on cost? (Round to the nearest tenth percent)
select one:
a a,
b,
c,
d.

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A purchaser paid for a computer system that originally cost 81,050 , If the markup was of the selling price, then what is the percent markup based on cost? (Round to the nearest tenth percent) select one: a a, b, c, d.