Question
\( \angle \mathrm{JZQ}=(9 \mathrm{x}+9)^{\circ} \) and \( \angle \mathrm{TLN}=(8 x+19)^{\circ} \), find the value of x . Type your answer in the boxes \( \square=\square \)
Ask by Lambert Mcdonald. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( x = 10 \)
Solution
To find the value of \( x \), let's set the two angles equal to each other since they are likely supplementary or equal in the given context:
\[
9x + 9 = 8x + 19
\]
Subtract \( 8x \) from both sides:
\[
x + 9 = 19
\]
Subtract 9 from both sides:
\[
x = 10
\]
**Answer:**
\( x = 10 \)
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution Beyond the Answer
To find the value of \( x \), we can set the two angles equal to each other, assuming they are congruent angles. Hence, we have: \[ (9x + 9) = (8x + 19) \] Now, let's solve for \( x \): 1. Subtract \( 8x \) from both sides: \[ 9x - 8x + 9 = 19 \] This simplifies to: \[ x + 9 = 19 \] 2. Next, subtract 9 from both sides: \[ x = 19 - 9 \] Thus, we find: \[ x = 10 \] So the solution is: \( \square=10 \)
