\( \angle \mathrm{JZQ}=(9 \mathrm{x}+9)^{\circ} \) and \( \angle \mathrm{TLN}=(8 x+19)^{\circ} \), find the value of x . Type your answer in the boxes \( \square=\square \)

To find the value of \( x \), we can set the two angles equal to each other, assuming they are congruent angles. Hence, we have: \[ (9x + 9) = (8x + 19) \] Now, let's solve for \( x \): 1. Subtract \( 8x \) from both sides: \[ 9x - 8x + 9 = 19 \] This simplifies to: \[ x + 9 = 19 \] 2. Next, subtract 9 from both sides: \[ x = 19 - 9 \] Thus, we find: \[ x = 10 \] So the solution is: \( \square=10 \)