What is the domain and range of the function $$ y=\sqrt{2 x-4} $$ ? a.) domain: $$ x \leq 0 $$ range: $$ y \leq 2 $$ b.) domain: $$ x \geq 2 $$, range: $$ y \geq 0 $$ c.) domain: $$ x \leq 2 $$, range: $$ y \leq 0 $$ d.) domain: $$ x \geq 0 $$ range: $$ y \geq 2 $$

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To determine the **domain** and **range** of the function $$ y = \sqrt{2x - 4} $$, let's analyze each part step by step.

### Domain:
The expression inside the square root, $$ 2x - 4 $$, must be **non-negative** because the square root of a negative number is not a real number. Therefore:
$$
2x - 4 \geq 0
$$
$$
2x \geq 4
$$
$$
x \geq 2
$$
So, the domain is all real numbers $$ x $$ such that $$ x \geq 2 $$.

### Range:
The square root function always yields **non-negative** results. Therefore, $$ y $$ must be greater than or equal to 0:
$$
y = \sqrt{2x - 4} \geq 0
$$
So, the range is all real numbers $$ y $$ such that $$ y \geq 0 $$.

### Conclusion:
The correct answer is:

**b.) domain: $$ x \geq 2 $$, range: $$ y \geq 0 $$**

**Answer:**  
**b.) domain: $$ x \geq 2 $$, range: $$ y \geq 0 $$**
The domain is all $$ x $$ where $$ x \geq 2 $$, and the range is all $$ y $$ where $$ y \geq 0 $$.

What is the domain and range of the function ?
a.) domain: range:
b.) domain: , range:
c.) domain: , range:
d.) domain: range:

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