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\begin{tabular}{l} Solve \( \frac{1}{2}+\frac{1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \) by rewriting the equation as a proportion. \\ Which proportion is equivalent to the original \\ equation? \\ \( \qquad \begin{array}{ll}\frac{x+2}{2 x}=\frac{x^{2}-7 x+10}{4 x} & \text { Name the true solution(s) to the equation. } \\ \frac{x-1}{2 x}=\frac{x^{2}-7 x+10}{4 x} & x=0 \\ x=1 \\ 2 x & \frac{x^{2}-7 x+10}{4 x} \\ x=8 \\ x=0, x=1, \text { and } x=8 \\ x=1 \text { and } x=8 \\ \text { There are no solutions. }\end{array} \) \\ \hline\end{tabular}

Ask by Chambers Patel. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

An equivalent proportion is \(\frac{x - 1}{2x} = \frac{x^2 - 7x + 10}{4x}\). The true solutions are \(x = 1\) and \(x = 8\).

Solution

To solve the equation: \[ \frac{1}{2} + \frac{1}{2x} = \frac{x^2 - 7x + 10}{4x} \] **Step 1: Rewrite the Equation as a Proportion** First, express all terms with a common denominator to facilitate rewriting the equation as a proportion. \[ \frac{1}{2} = \frac{2x}{4x} \quad \text{and} \quad \frac{1}{2x} = \frac{2}{4x} \] Substituting these into the original equation: \[ \frac{2x}{4x} + \frac{2}{4x} = \frac{x^2 - 7x + 10}{4x} \] Combine the numerators on the left side: \[ \frac{2x + 2}{4x} = \frac{x^2 - 7x + 10}{4x} \] Since the denominators are the same and non-zero, set the numerators equal to each other: \[ 2x + 2 = x^2 - 7x + 10 \] **Step 2: Formulate the Equivalent Proportion** Rearrange the equation to standard quadratic form: \[ x^2 - 9x + 8 = 0 \] This can be written as the proportion: \[ \frac{x - 1}{2x} = \frac{x^2 - 7x + 10}{4x} \] **Step 3: Solve the Quadratic Equation** Factor the quadratic equation: \[ x^2 - 9x + 8 = (x - 1)(x - 8) = 0 \] Setting each factor to zero gives the potential solutions: \[ x - 1 = 0 \quad \Rightarrow \quad x = 1 \] \[ x - 8 = 0 \quad \Rightarrow \quad x = 8 \] **Step 4: Verify Solutions** Ensure that the solutions do not make any denominators zero: - For \( x = 1 \): Denominators \( 2x \) and \( 4x \) become 2 and 4, respectively – valid. - For \( x = 8 \): Denominators \( 2x \) and \( 4x \) become 16 and 32, respectively – valid. **Conclusion** - **Equivalent Proportion:** \(\displaystyle \frac{x - 1}{2x} = \frac{x^2 - 7x + 10}{4x}\) - **True Solutions:** \( x = 1 \) and \( x = 8 \) **Final Answer:** After simplifying, an equivalent proportion is (x – 1)/2x = (x² – 7x + 10)/4x. The true solutions to the equation are x = 1 and x = 8.

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The Deep Dive

To solve the equation \( \frac{1}{2}+\frac{1}{2 x}=\frac{x^{2}-7 x+10}{4 x} \), we can start rewriting it in a way that helps us find a proportion. By getting a common denominator on the left side, we can transform it into \( \frac{x+2}{2x} = \frac{x^2 - 7x + 10}{4x} \). Cross-multiplying, we end up with \( 4(x + 2) = 2(x^2 - 7x + 10) \). The next step is to solve the quadratic equation we formed by simplifying this proportion. After distributing and collecting like terms, we can factor the left side: \( 2x^2 - 6x = 0 \) breaks down to \( 2x(x - 3) = 0 \). This gives us two potential solutions: \( x = 0 \) and \( x = 3 \). However, substituting back into the original equation reveals that \( x = 0 \) is invalid due to division by zero! Therefore, the only valid solution is \( x = 3 \). Thus, the only true solution to the equation is \( x = 3 \). Happy solving!

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