What is the first step to solve the inequality \( x-5<\frac{x}{6} \) A. Divide both sides of the inequality by 6 to simplify: \( \frac{x}{6}-\frac{5}{6}<6 \) B. Divide both sides of the inequality by \( x \) to simplify: \( 1-\frac{5}{x}<6 \) C. Multiply both sides of the inequality by \( x \) to simplify: \( x-5<6 \) D. Multiply both sides of the inequality by 6 to simplify: \( 6 x-30<x \)

Simplify. \( 6 v+3 v \)

(i) \( 2.25 \% \) of \( x \) is 630

Simplify the following: (1) \( \frac{x-1}{x^{2}+3 x+2} \div\left[\frac{x-3}{x+1}-\frac{x-4}{x+2}\right] \) (2) \( \frac{\frac{6 x+5}{x-5}-1}{\frac{3 x+20}{x-5}+2} \) (3) \( \frac{a^{2}+\left(1-a^{2}\right)}{(1+a) a} \times \frac{(1+a) a}{a^{2}-\left(1-a^{2}\right)} \)

Simplify the following: (1) \( \frac{x-1}{x^{2}+3 x+2} \div\left[\frac{x-3}{x+1}-\frac{x-4}{x+2}\right] \) (2) \( \frac{\frac{6 x+5}{x-5}}{\frac{3 x+20}{x-5}+2} \) (3) \( \frac{a^{2}+\left(1-a^{2}\right)}{(1+a) a} \times \frac{(1+a) a}{a^{2}-\left(1-a^{2}\right)} \)

Example Solve the equation \( 2 x^{2}+4 x-10=0 \) with error precision 0.05