The cross tube is made from two identical cylindrical glass tubes of radius \( r=1.073 \mathrm{~cm} \), joined together in the shape of an \( X \), such that each tube "leg" makes an angle \( \theta=57.06 \) degrees with respect to the horizontal bench top on which the cross tube rests. The vertical distance from the bench top to the mid point of the join (red dot) is \( \mathrm{d}_{1}=16.81 \mathrm{~cm} \), as shown in the diagram, and then a further vertical distance \( \mathrm{d}_{2}=22.27 \mathrm{~cm} \) from the mid point to the surface of the water filling the tube, as shown. Both top ends of the tubes are open to the atmosphere. Find the pressure difference (in Pa) between the pressure at the red dot (mid-point of the cross tube join) and atmospheric pressure. Use \( g=9.8 \mathrm{~ms}^{-2} \) as the Earth's gravitational field strength. Please enter your answer so in scientific notation that is correct to exactly 3 significant figures
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