Pa lontano Calcola l'altezza di un campanile, Sapendo che da un bar distante 80 metri da esso si vede la sun cima secondo un angolo di \( 42^{\circ} \).

If \( x \) is in the third quadrant, then \( \cot x \) in terms of \( \sec x \) is A) \( \frac{\sqrt{\sec ^{2} x-1}}{\sec ^{2} x-1} \) B) \( -\frac{\sqrt{\sec ^{2} x-1}}{\sec ^{2} x-1} \) C) \( -\frac{\sqrt{\sec ^{2} x+1}}{\sec ^{2} x-1} \)

11) The measure of the smallest positive angle satisfy the relation : \( 2 \sin \theta=-1 \) is \( \begin{array}{lll}\text { (a) } 30^{\circ} & \text { (b) } 120^{\circ} & \text { (c) } 210^{\circ} y=x\end{array} \)

\( \log ( \cos \theta ) + \log ( \sec \theta ) = \ldots \ldots \ldots . . , \theta \in [ 0 , \frac { \pi } { 2 } ] \)

The value of \( \sec \left(300^{\circ}\right) \sin \left(270^{\circ}-\theta\right)+\tan \left(-45^{\circ}\right) \cos \left(360^{\circ}-\theta\right) \) is \( \begin{array}{llll}\text { (a) }-3 \sin \theta & \text { (b) }-3 \cos \theta & \text { (c) } 3 \cos \theta & \text { (d) } 0\end{array} \)

3. Выразите в градусной мере величины углов: а) \( 3 ; \) б) \( -\frac{\pi}{9} \); в) \( \frac{5 \pi}{12} \); г) \( \frac{7 \pi}{3} \); д) 4,2 ; е) \( \frac{\pi}{5} \); ж) \( 0,6 \pi \); з) \( \frac{25}{18} \pi \).