Lee Stanley
08/23/2023 · Senior High School
Câu 3. Tam giác \( A B C \) có \( A B=3, A C=6, \widehat{B A C}=60^{\circ} \). A) \( B C^{2}=A B^{2}+A C^{2}-2 A B \cdot A C \cdot \cos A \) b) Độ dài cạnh \( B C \) bằng \( 3 \sqrt{3} \). c) Bán kính đường tròn ngoaại tiếp tam giác \( A B C \) là \( R=2 \). \( S \) d) Diện tích tam giác \( A B C \) bằng \( 9 \sqrt{3} \).
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Câu 3. Tam giác \( ABC \) có \( AB = 3 \), \( AC = 6 \), góc \( BAC = 60^\circ \).
a) \( BC^2 = AB^2 + AC^2 - 2 \times AB \times AC \times \cos A \)
b) Độ dài cạnh \( BC \) là \( 3\sqrt{3} \).
c) Bán kính đường tròn ngoại tiếp tam giác \( ABC \) là \( R = 2 \).
d) Diện tích tam giác \( ABC \) là \( 9\sqrt{3} \).
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