Q:
\( 37 ; 33 ; 29 ; x ; 21 ; \ldots \).
Write down the value of \( x \).
Determine the \( n^{\text {th }} \) term of the number pattern.
Determine the \( 15^{\text {th }} \) term of the sequence.
Which term is the first to have a negative value.
Q:
Evalúa la integral \( \int \frac{x-1}{2 x+4} d x \)
Escoge 1 respuesta:
(A) \( \frac{1}{2} x-\frac{1}{2} \ln |x+2|+C \)
(3) \( \frac{1}{2} x-\ln |x+2|+C \)
\( \frac{1}{2} x-\frac{3}{2} \ln |x+2|+C \)
\( \frac{1}{2} x-2 \ln |x+2|+C \)
Q:
Si la siguiente serie geométrica infinita converge, encuentra su suma.
\( 1+\frac{3}{5}+\left(\frac{3}{5}\right)^{2}+\left(\frac{3}{5}\right)^{3} \ldots \)
1.5
2
25
2
Q:
\( y=\frac{\sin x}{2},-\pi \leq x \leq \pi \)
Use differentiation to determine the co-ordinates of the maximum and minimum
turning points. Also distinguish between the maximum and minimum turning points
of the given function by using the second derivative.
Q:
c) \( 8+(-18): 3= \)
Q:
Approximate the area under the graph of \( f(x) \) and above the \( x \)-axis
using \( n \) rectangles.
\( f(x)=2 x+3 \) from \( x=0 \) to \( x=2 ; n=4 \); use right endpoints
O. 11
B. 13
C. 17
D. 15
Q:
Mr Zwane is twice as old as his son. Ten years ago he was three
times as old as his son.
If the son is * years old, determine the age of Mr Zwane in terms of
*
Find the ages of Mr Zwane and his son ten years ago in terms of \( x \).
Determine the present age of Mr Zwane.
Q:
\[ \quad \begin{array}{l}\text { Approximate the area under the graph of } f(x) \text { and above the } x \text {-axis } \\ \text { using } n \text { rectangles. }\end{array} \]
\( f(x)=2 x+3 \) from \( x=0 \) to \( x=2 ; n=4 \); use right endpoints
Q:
PENSAMIENTO MATEMÁTICO 1
3. Homero acaba de abrir una bolsa de chocolates confitados y los clasifica por color
encontrando 5 naranjas, 7 verdes, 6 azules, 8 amarillos, 5 rojos, y 6 cafés. Realiza
una gráfica de columnas para representar lo que encontró en la bolsa
-
Q:
2.4 Prove that the equation \( \frac{3}{4} x^{2}+9 x=-27 \) has only one rational root,
namely \( x=-6 \), without solving the equation.
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