Isabella ran taps around the park. She ran a total of \( 1 \frac{3}{4} \) miles. Each lap is \( \frac{1}{4} \) mile. Which equation can lsabella use to find out how many laps she ran? A. \( \frac{1}{4} \div 1 \frac{3}{4}=\frac{1}{7} \) C. \( 1 \frac{3}{4} \div \frac{1}{4}=7 \) C. \( 1 \frac{3}{4}-\frac{1}{4}=1 \frac{1}{2} \) D. \( 1 \frac{3}{4}+\frac{1}{4}=2 \)

Consider the number pattern below: \[ \frac{-3}{5} ; \frac{-6}{9} ; \frac{-9}{13} ; \ldots . \ldots \] Determine the next two terms of the number pattern. Determine the \( n^{\text {th }} \) term of the number pattern.

Calcula las siguientes potencias: \( \begin{array}{ll}\text { a) } 3^{-4}=\frac{\square}{\square} & \text { b) }(3 / 4)^{-2}=\frac{\square}{\square}\end{array} \)

Determine whether the following statment is true or false. The graph of \( y=\frac{1}{7} g(x) \) is the graph of \( y=g(x) \) stretched by a factor of 7 . Choose the correct answer below. A. True, because the graph of the new function is obtained by adding 7 to each \( x \)-coordinate. Balse, because the graph of the new function is obtained by multiplying each \( y \)-coordinate of \( y=g(x) \) by \( \frac{1}{7}<1 \). C. True, because the graph of the new function is obtained by multiplying each \( y \)-coordinate of \( y=g(x) \) by 7 and \( 7>1 \). D. False, because the graph of the new function is obtained by adding 7 to each \( x \)-coordinate.

The postal service of a country charges \( \$ 0.36 \) postage for a letter weighing up to 1 ounce, plus \( \$ 0.26 \) for each additional ounce up to 5 ounces. Letters weighing more than 5 ounces do not qualify for these rates. \( C(x)=\left\{\begin{array}{ll}\$ \square & \text { if } 0<x \leq 1 \\ \text { (a) Write a piecewise-defined function } C \text { for the postage charged for a letter weighing } x \text { ounces. } \\ \$ \square & \text { if } 3<x \leq 4 \\ \$ \square & \text { if } 4<x \leq 5\end{array}\right. \)

8. \( -5 \frac{1}{3}-\left(-6 \frac{2}{3}\right) \)