In exercises 18 to 22 , find the limit, If the limit does not exist, justify your answe (18) Limit of the function \( f(x)=\frac{|x-3|}{x-3} \) as \( x \) tends to 3 )rom the right:

\( \left. \begin{array} { l } { \lim _ { x \rightarrow 2 } \frac { x - 2 } { x ^ { 2 } - x - 2 } } \\ { \left. \begin{array} { l | l | l | l | l | l | l | l | } { } \\ { x } & { 1.9 } & { 1.99 } & { 1.999 } & { 2 } & { 2.001 } & { 2.01 } & { 21 } \\ \hline f ( x ) & { } & { } & { } & { } & { } \end{array} \right. } \end{array} \right. \)

Xosmas integrallarni hisoblang yoki uzoqlashuvchi ekanini aniqlang \[ \int_{e^{2}}^{\infty} \frac{d x}{x \ln \ln x} \]

Berilgan qatorlarni absolyut va shartli yaqinlashishga tekshiring. \[ \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{(n+1) \ln (n+1)} \]

\( \int 9 ^ { x ^ { k } + r _ { x } } . \)

1. \( \lim _{x \rightarrow 2} \frac{x-2}{x^{2}-x-2} \) \begin{tabular}{l|l|l|l|l|l|}\( x \) & 1.9 & 1.99 & 1.999 & 2 & 2.001 \\ \hline\( f(x) \) & 2.01 & 2.1 \\ \hline\end{tabular}