Qview Question 14, 6.5.11 Save \( \begin{array}{l}\text { Find the function value using coordinates of points on the unit circle. Give the exact } \\ \text { answer. } \\ \sin (-9 \pi)\end{array} \) \( \begin{array}{l}\text { A. } \sin (-9 \pi)=\square \\ \text { (Simplify your answer, including any radicals. Use integers or fractions for any } \\ \text { numbers in the expression.) }\end{array} \) B. The function is undefined.

11) The measure of the smallest positive angle satisfy the relation : \( 2 \sin \theta=-1 \) is \( \begin{array}{lll}\text { (a) } 30^{\circ} & \text { (b) } 120^{\circ} & \text { (c) } 210^{\circ} y=x\end{array} \)

(6) The value of \( \sec \left(300^{\circ}\right) \sin \left(270^{\circ}-\theta\right)+\tan \left(-45^{\circ}\right) \cos (3 M-9) \) is \( \begin{array}{lll}\text { (a) }-3 \sin \theta & \text { (b) }-3 \cos \theta & \text { (c) } 3 \cos \theta\end{array} \) (7) If the product of two roots of the equation : \( (k-2) x^{2}-6 x+12=0 \) equals 3

3. Выразите в градусной мере величины углов: а) \( 3 ; \) б) \( -\frac{\pi}{9} \); в) \( \frac{5 \pi}{12} \); г) \( \frac{7 \pi}{3} \); д) 4,2 ; е) \( \frac{\pi}{5} \); ж) \( 0,6 \pi \); з) \( \frac{25}{18} \pi \).

JSTION 11 Prove the following identity: \( \frac{\cos ^{2}\left(90^{\circ}+\theta\right)}{\cos (-\theta)+\sin \left(90^{\circ}-\theta\right) \cos \theta}=\frac{1}{\cos \theta}-1 \) Determine the general solution of: \( \tan x \sin x+\cos x \tan x=0 \). Consider the following expression: \( 2 \sin ^{2} 3 x-\sin ^{2} x-\cos ^{2} x \) 11.3.1 Simplify the expression to a single trigonometric ratio of \( x \). 11.3.2 Write down the maximum value of the expression.

\( \log ( \cos \theta ) + \log ( \sec \theta ) = \ldots \ldots \ldots . . , \theta \in [ 0 , \frac { \pi } { 2 } ] \)