Find the standard form equation for a hyperbola with vertices at \( (0,6) \) and \( (0,-6) \) and asymptote \( y=\frac{3}{4} x \) \( \square \)

Convert the polar coordinate \( \left(2, \frac{5 \pi}{6}\right) \) to Cartesian coordinates. \( \mathrm{x}=\square \) Preview \( \mathrm{y}=\square \) Preview

Rewrite the Cartesian equation \( y=7 x^{2} \) as a polar equation. \( r(\theta)=\square \) Preview Enter theta for \( \theta \) if needed.

Find the standard form equation for a hyperbola with vertices at \( (0,6) \) and \( (0,-6) \) and asymptote \( y=\frac{3}{4} x \) \( \square \)

Convert the point with polar coordinates \( \left(2, \frac{5 \pi}{6}\right) \) to Cartesian coordinates. Enter exact values. The point is: Get help: Video

Convert the Cartesian coordinate \( (-5,-4) \) to polar coordinates, \( 0 \leq \theta<2 \pi, r>0 \) \( r=\square \) Preview \( \theta=\square \) Preview Get help: Video Video