Convert the point with polar coordinates \( \left(2, \frac{5 \pi}{6}\right) \) to Cartesian coordinates. Enter exact values. The point is: Get help: Video

9. (3 points) What kind of asymptotes(s) does the function \( y=\frac{4 x^{2}+3 x-1}{x^{2}-x}=\frac{(4 x-1)(x+1)}{x(x-1)} \) have? \( \begin{array}{ll}\text { A) Horizontal : } y=4 \text {, Vertical : } x=0, x=1 & \text { (B) Horizontal : } y=0 \text {, Vertical : } x=0, x=1 \\ \text { (C) Slant : } y=4 \text {, Vertical : } x=0 & \text { (D) Slant : } y=4 x-3 \text {, Vertical : } x=1\end{array} \)

Convert the Cartesian coordinate \( (-5,-4) \) to polar coordinates, \( 0 \leq \theta<2 \pi, r>0 \) \( r=\square \) Preview \( \theta=\square \) Preview Get help: Video Video

Convert the polar coordinate \( \left(2, \frac{5 \pi}{6}\right) \) to Cartesian coordinates. \( \mathrm{x}=\square \) Preview \( \mathrm{y}=\square \) Preview

Find the standard form equation for a hyperbola with vertices at \( (0,6) \) and \( (0,-6) \) and asymptote \( y=\frac{3}{4} x \) \( \square \)

Rewrite the Cartesian equation \( y=7 x^{2} \) as a polar equation. \( r(\theta)=\square \) Preview Enter theta for \( \theta \) if needed.