Solve the Quadratic Equation From Fist Pinciple. \[ y=a x^{2}+b x+c \] to \( y=\frac{-b \pm \sqrt{4 a c}-b^{2}}{29} \)

\( \frac{\mathbf{2}^{2004}-\mathbf{2}^{2002}}{2^{2001}}=? \) \( \begin{array}{lllll}\text { A) } 2 & \text { B) } 4 & \text { C) } 6 & \text { D) } 8 & \text { E) }\end{array} \)

(4) \( (x+3)^{3}=343 \)

\[ h(x)=x^{3}+a x^{2}+b x+c \] The function \( h \) is defined above, where \( a, b \), and \( c \) are integer constants. If the zeros of the function are \( -5,6 \), and 7 , what is the value of \( c \) ?

в) \( \left\{\begin{array}{l}4 x-7 y=30 \\ 4 x-5 y=90\end{array}\right. \)

Use the power of a power property to simplify: \( (2y^{5})^{2} \)