2656. Найдите значение буквенного выражения \( 7+x \) при \( x \), равном: \( \begin{array}{lllll}\text { а) } 0 ; & \text { б) } 3 ; & \text { в) }-1 ; & \text { г) }-4 ; & \text { д) }-7 ;\end{array} \) е) -10.

b. \( \frac{1}{3} \times(\sqrt{5}-\sqrt{2}) \times(\sqrt{5}+\sqrt{2}) \)

\[ \mathrm{x}+\mathrm{y}=6 \text {, } \] It is known that the solutions are integers. \( \mathrm{x}^{y}=\mathrm{y}^{\mathrm{x}} \) \( \quad \) a. \( \{(1,5),(5,1)\} \) b. \( \{(5,5),(-10,16),(16,-10)\} \) c. \( \{(3,3),(4,2),(2,4)\} \) d. \( \{ \) all integers divisible by 3 and 2\( \} \) e. None of the above

Move Variables to one side

\begin{tabular}{c}\hline SOLVING EQUATIONS \\ \hline \( \begin{array}{c}\text { Simplify Each Side } \\ \text { by combining like terms }\end{array} \) \\ \hline \( \begin{array}{c}\text { Move Variables } \\ \text { to one side }\end{array} \) \\ \hline Solve \\ \hline Using inverse operations \\ \hline\end{tabular}

1. \( \left(2 \frac{1}{4} x^{6} y^{2}\right) \cdot\left(-\frac{2}{3} x y^{3}\right)^{2} \cdot\left(3 x^{5} y^{2}\right)^{3} \) birhadlisininquavatila amsali farqinitapin. \( \begin{array}{llll}\text { A) } 5 & \text { B) } 13 & \text { (C) } 10 & \text { D) } 18\end{array} \)