Make a table of ordered pairs for the equation \( y=\frac{1}{2} x-3 \)

ข) \( x+y=2 \)

г) \( \frac{3-x}{12}=7-\frac{x+5}{20} \)

6) \( (x-7)^{2}=(2-x)^{2} \)

9) (Q. 4 ball.) Guruhlash usulidan foydalanib, ko'paytuvchilarga ajrating: \[ \begin{array}{ll}x^{3}-5 x^{2}+m x-5 m \\ \text { A) }(x-5)(x+m) & \text { B) }(x-5)\left(x^{2}+m\right) \\ \text { C) }(x+5)\left(x^{2}-m\right) & \text { D) }(x-5)(x-m)\end{array} \]

10) \( ( \) Q. 4 ball. \( ) \) Umumiy ko'paytuvchini qavsdan chiqaring: \( 49 a^{7} b^{4}-35 a^{6} b^{4} \) \( \begin{array}{ll}\text { A) } 7 a^{6} b^{4}(7 a-5) & \text { B) } 7 a^{6} b^{3}(7 a-5 b) \\ \text { C) } 7 a^{6} b^{4}(a-5) & \text { D) } 7 a^{6} b^{4}(7 a+5)\end{array} \)