USING EQUATIONS to solve WORD PROBLEMS Directions: Set up and solve an equation for each problem below. 5. The length of a rectangle is one more than four times its width. If the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle.

solve the Pollowing systew using. \( A^{-1} \) \( \begin{array}{l}4 x+2 y-z=5 \\ 3 x-y-z=-2 \\ x+y-z=0\end{array} \)

\[ f(x)=x^{2}-42 x+80 \] The function \( f \) is defined by the given equation. Which of the following equivalent forms of the equation displays the zeros of the function as constants or coefficients? (A) \( f(x)=x^{2}-5 x-37 x+80 \) (B) \( f(x)=(x-2)(x-40) \) (C) \( f(x)=x(x-42)+80 \) (D) \( f(x)=(x-21)^{2}-361 \)

If \( f:]-4,7[\longrightarrow \mathbb{R} \) where \( f(x)=x+2 \), then \( f(x) \) is negative when \( x \in \ldots \ldots \) \( \begin{array}{llll}\text { (a) }]-4,-2[ & \text { (b) }]-\infty,-2[ & \text { (c) }]-2, \infty[ & \text { (d) }]-2,7[ \end{array} \)

\( \begin{array}{ll}\text { Solve for } x: \\ 1.1 .1 & x(x-10)=0 \\ 1.1 .2 & 7 x^{2}-5 x-6=0 \text { (correct to TWO decimal places) } \\ 1.1 .3 & (x+2)(2 x-4) \geq 0\end{array} \)

\( \left\{ \left. \begin{array} { l } { 2 x - 3 < ( x + 1 ) ^ { 2 } - x ( x - 1 ) } \\ { x + 3 - 2 x \geq 4 } \end{array} \right. \quad [ - 4 < x \leq - 1 ] \right. \)