$$ y=\frac{\sin x}{2},-\pi \leq x \leq \pi $$ Use differentiation to determine the co-ordinates of the maximum and minimum turning points. Also distinguish between the maximum and minimum turning points of the given function by using the second derivative.

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Rojas Bright · Accepted Answer

The minimum turning point is at $$ \left(-\frac{\pi}{2}, -\frac{1}{2}\right) $$ and the maximum turning point is at $$ \left(\frac{\pi}{2}, \frac{1}{2}\right) $$.

\( y=\frac{\sin x}{2},-\pi \leq x \leq \pi \) Use differentiation to determine the co-ordinates of the maximum and minimum turning points. Also distinguish between the maximum and minimum turning points of the given function by using the second derivative.

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\( y=\frac{\sin x}{2},-\pi \leq x \leq \pi \) Use differentiation to determine the co-ordinates of the maximum and minimum turning points. Also distinguish between the maximum and minimum turning points of the given function by using the second derivative.

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