Tema
Q:
6 A plane flies on a true bearing of \( 280^{\circ} \mathrm{T} \) at \( 600 \mathrm{~km} / \mathrm{h} \)
after taking off at 1300 hours. To the nearest
kilometre, how far north of its starting position
is it at 1530 hours?
Q:
Solve the equation for exact solutions over the interval \( [0,2 \pi) \)
\( 2 \tan 3 x=2 \)
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is \( \left\{\frac{\pi}{12}, \frac{5 \pi}{12}, \frac{3 \pi}{4}, \frac{13 \pi}{12}, \frac{17 \pi}{12}, \frac{7 \pi}{4}\right\} \).
(Type an exact answer, using \( \pi \) as needed. Type your answer in radians. Use integers or fractions for any numbers in the expression. Use a com
B. The solution is the empty set.
Q:
When evaluating the expression \( \tan ^{-1}\left(-\frac{\sqrt{3}}{3}\right) \), the angle obtained is ...
Q:
Solve \( 8 \sin \left(\frac{\pi}{5} x\right)=4 \) for the four smallest positive solutions
Q:
Solve \( \sin ^{2}(t)=-8 \cos (t) \) for all solutions \( 0 \leq t<2 \pi \)
Q:
(1) จงหาค่าของ \( 2 \sin 20^{\circ}+\cot 68^{\circ} \)
Q:
4) \( \operatorname{Si} \tan \Phi=\frac{\sqrt{6}}{3} \), donde " \( \Phi \) " es un ángulo agudo, calcular:
\( \mathrm{P}=\sqrt{3} \operatorname{Sec} \Phi+\sqrt{2} \operatorname{Csc} \Phi \)
Q:
Given that \( \tan 75^{\circ}=2+\sqrt{3} \) hence determine \( \tan 15^{\circ} \) leaving your answer in the form
\( a+b \sqrt{c} \)
Q:
Nite the expression below in surd form and rationalize the denominator
\[ \frac{1-\cos 60^{\circ}}{1+\operatorname{tim} 30^{\circ}} \]
Q:
4) \( \operatorname{Si} \tan \Phi=\frac{\sqrt{6}}{3} \), donde \( \Phi \) ' es un ángulo agudo, calcular:
\( P=\sqrt{3} \operatorname{Sec} \Phi+\sqrt{2} \operatorname{Csc} \Phi \)
Pon a prueba tus conocimientos sobre Trigonometría!
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