(2) \( \int \frac{10}{\sqrt[3]{3-5 x}} \mathrm{~d} x \);
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To solve the integral \( \int \frac{10}{\sqrt[3]{3-5 x}} \mathrm{~d} x \), we can use substitution. Let \( u = 3 - 5x \), which gives \( \mathrm{d}u = -5 \mathrm{d}x \) or \( \mathrm{d}x = -\frac{1}{5} \mathrm{d}u \). Substituting this into the integral transforms it into: \[ \int \frac{10}{\sqrt[3]{u}} \left( -\frac{1}{5} \right) \mathrm{d}u = -2 \int u^{-\frac{1}{3}} \mathrm{d}u. \] Now, using the power rule for integration: \[ -2 \cdot \frac{u^{\frac{2}{3}}}{\frac{2}{3}} + C = -3u^{\frac{2}{3}} + C. \] Substituting back for \( u \): \[ -3(3 - 5x)^{\frac{2}{3}} + C. \] Thus, the final answer for the integral is: \[ -3(3 - 5x)^{\frac{2}{3}} + C. \] Don't forget to simplify and express your answer clearly! And remember to always check your work by differentiating your answer to see if you get the original integrand back.