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and Similar Triangles Select the correct choices that complete the sentence below. An isosceles right triangle has one \( \square \) angle and \( \square \) equal sides.

Ask by Gonzalez Burton. in the United States
Feb 03,2025

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Answer

An isosceles right triangle has one right angle and two equal sides.

Solution

To complete the sentence regarding an isosceles right triangle: 1. An isosceles right triangle has one **right** angle. 2. An isosceles right triangle has **two** equal sides. So the completed sentence is: "An isosceles right triangle has one **right** angle and **two** equal sides."

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Extra Insights

An isosceles right triangle has one \( 90^\circ \) angle and \( 2 \) equal sides. The unique properties of an isosceles right triangle make it a favorite among geometry enthusiasts! It has angles of \( 90^\circ \), \( 45^\circ \), and \( 45^\circ \), creating a perfect balance that can be found in many designs—from the blueprints of buildings to the simplistic elegance of a slice of pizza! For real-world applications, isosceles right triangles appear in various fields, such as architecture and engineering. For example, the roof trusses of a house often utilize this triangle type to achieve both aesthetic appeal and structural stability. So next time you spot a triangle, remember the hidden geometrical wonders at play!

Related Questions

Exercice 82 Le plan est rapporté à un repère orthonormal direct \( (0, \vec{u}, \vec{v}) \). On appelle \( f \) l'application qui, à tout point \( M \) d'affixe \( z(z \neq-1) \) associe le point \( M^{\prime} \) d'affixe \( z^{\prime} \) telle que : \( z^{\prime}=\frac{-i z-2}{z+1} \). Soient A, B et C les points d'affixes respectives \( a=-1, b=2 i \) et \( c=-i \). 1) Soit \( C^{\prime} \) l'image du point \( C \) par \( f \). Donner l'affixe \( c^{\prime} \) du point \( C^{\prime} \) sous forme algébrique, puis sous forme trigonométrique. 2) Calcule l'affixe \( d \) du point \( D \) ayant pour image par \( f \) le point \( D^{\prime} \) d'affixe \( d^{\prime}=\frac{1}{2} \). 3) Pour tout nombre complexe \( z \) différent de -1 , on note \( p \) le module de \( z+1 \) (c'est-à-dire \( |z+1|=p) \) et \( p^{\prime} \) le module de \( z^{\prime}+i\left(\right. \) c'est-à-dire \( \left.\left|z^{\prime}+i\right|=p^{\prime}\right) \). a) Démontre que pour tout nombre complexe \( z \) différent de -1 , on a : \( p p^{\prime}=\sqrt{5} \). b) Si le point \( M \) appartient au cercle \( (\Gamma) \) de centre A et de rayon 2 , montre qu'alors \( M^{\prime}=f(M) \) appartient à un cercle ( \( \left.\Gamma^{\prime}\right) \) dont on précisera le centre et le rayon. 4) Pour tout nombre complexe \( z \) différent de -1 , on considère le nombre complexe \( \omega=\frac{z-2 t}{z+1} \). a) Interprète géométriquement l'argument du nombre complexe \( \omega \). b) Montre que \( z^{\prime}=-i \omega \). c) Détermine l'ensemble \( (F) \) des points \( M \) d'affixe \( z \) telle que \( z^{\prime} \) soit un réel non nul. d) Vérifie que le point \( D \) appartient aux ensembles \( (\Gamma) \) et \( (F) \). 5) Représente les ensembles \( (\Gamma) \), (F) et \( \left(\Gamma^{\prime}\right) \) en prenant 4 cm pour unité graphique.
Geometry Mali Feb 03, 2025
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