Question
A function of the form \( f(x)=a b^{x} \) is modified so that the \( b \) value remains the same but the \( a \) value is increased by 2 . How do the domain and range of the new function compare to the domain and range of the original function? Check all that apply. The range stays the same. The range becomes \( y>2 \). The domain stays the same. The domain becomes \( x>2 \). The domain becomes becomes \( y \geq 2 \).
Ask by Wright Park. in the United States
Jan 24,2025
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Tutor-Verified Answer
Answer
The domain and range remain the same after increasing the \( a \) value by 2.
Solution
When modifying the function \( f(x) = a b^{x} \) by increasing the \( a \) value by 2 (resulting in a new function \( f_{\text{new}}(x) = (a + 2) b^{x} \)), let's analyze how the domain and range are affected:
1. **Domain:**
- **Original Function:** The domain of an exponential function like \( f(x) = a b^{x} \) is all real numbers, \( \mathbb{R} \).
- **Modified Function:** The modification \( (a + 2) \) does not affect the input values \( x \). Therefore, the domain remains unchanged.
2. **Range:**
- **Original Function:** For \( a > 0 \) and \( b > 0 \), the range is \( (0, \infty) \).
- **Modified Function:** Adding 2 to \( a \) (assuming \( a + 2 > 0 \)) scales the output by a positive factor but doesn't change the fundamental nature of the exponential growth or decay. Hence, the range remains \( (0, \infty) \).
**Conclusion:**
- The **domain stays the same**.
- The **range stays the same**.
**Therefore, the correct statements are:**
- **The range stays the same.**
- **The domain stays the same.**
**Answer:**
Both “The range stays the same” and “The domain stays the same” are correct.
Reviewed and approved by the UpStudy tutoring team
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Beyond the Answer
The modified function takes the form \( f(x) = (a + 2)b^{x} \). The domain of both the original and modified functions remains all real numbers, since exponential functions are defined for every \( x \). So, the domain stays the same. However, the range of the original function is typically \( y > 0 \) if \( a > 0 \), and when \( a \) is increased by 2, the range shifts to \( y > 2 \). Therefore, the range of the new function indeed becomes \( y > 2 \). So, the correct comparisons are: - The range becomes \( y > 2 \). - The domain stays the same.