\( 100=6 \int_{0.325}^{x_{2}} \frac{d x}{0.00488} \) what is the value of \( x_{2} \) ?
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To solve for \( x_{2} \), we start by simplifying the equation. First, multiply both sides by \( 0.00488 \): \[ 100 \times 0.00488 = 6 \int_{0.325}^{x_{2}} d x \] This gives us: \[ 0.488 = 6 \left[ x_{2} - 0.325 \right] \] Dividing both sides by 6, we have: \[ \frac{0.488}{6} = x_{2} - 0.325 \] Calculating \( \frac{0.488}{6} \) gives approximately \( 0.08133 \). Now we can isolate \( x_{2} \): \[ x_{2} = 0.08133 + 0.325 \] Thus: \[ x_{2} \approx 0.40633 \] So the value of \( x_{2} \) is approximately \( 0.406 \).