\( \begin{array}{ll}\text { 85. Express } \ln 2 x=4 \text { in exponential form } & \text { 24. Express } e^{5}=x \text { in logarithmic form } \end{array} \)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Extra Insights
To express \( \ln 2x = 4 \) in exponential form, we can use the property that if \( \ln a = b \), then \( a = e^b \). Therefore, we get \( 2x = e^4 \). This makes sense because we are “undoing” the natural logarithm by exponentiating both sides. For the second equation, to express \( e^5 = x \) in logarithmic form, we again use the property of logarithms. This tells us that if \( a^b = c \), then \( \log_a c = b \). Here, we can rewrite it as \( \ln x = 5 \). This means if we want to find \( x \) in terms of its logarithm, we can express it as the natural log of \( x \) being equal to 5!