In another set-up, a student has prepared a 3.64 g sample of CuCNS. How
many molecules of CuCNS exist in this sample?
(Avogadro’s constant )

Ask by Hart Wheeler. in South Africa

Nov 26,2024

Question

In another set-up, a student has prepared a 3.64 g sample of CuCNS. How many molecules of CuCNS exist in this sample? (Avogadro's constant $$ =6.022 	imes 10^{23} \mathrm{~mol}^{-1} $$ )

UpStudy AI · Accepted Answer

To find the number of molecules of CuCNS in a 3.64 g sample, we need to follow these steps:

1. Calculate the molar mass of CuCNS.
2. Determine the number of moles of CuCNS in the sample.
3. Use Avogadro's constant to find the number of molecules of CuCNS.

Let's start by calculating the molar mass of CuCNS:

The molar mass of CuCNS can be calculated by adding the atomic masses of copper (Cu), carbon (C), nitrogen (N), and sulfur (S).

The atomic masses are:
- Copper (Cu) = 63.55 g/mol
- Carbon (C) = 12.01 g/mol
- Nitrogen (N) = 14.01 g/mol
- Sulfur (S) = 32.07 g/mol

Therefore, the molar mass of CuCNS = 63.55 + 12.01 + 14.01 + 32.07 = 121.64 g/mol

Next, we need to determine the number of moles of CuCNS in the 3.64 g sample:

Number of moles = mass of sample / molar mass of CuCNS

Substitute the values:
Number of moles = 3.64 g / 121.64 g/mol

Now, we can use Avogadro's constant to find the number of molecules of CuCNS:

Number of molecules = number of moles * Avogadro's constant

Substitute the values:
Number of molecules = (3.64 g / 121.64 g/mol) * 6.022 * 10^23 mol^-1

Let's calculate this.
Calculate the value by following steps:
- step0: Calculate:
  $$\left(\frac{3.64}{121.64}ight)	imes 6.022	imes 10^{23}$$
- step1: Divide the terms:
  $$\frac{91}{3041}	imes 6.022	imes 10^{23}$$
- step2: Rewrite the expression:
  $$\frac{91}{3041}	imes 6022	imes 10^{20}$$
- step3: Multiply:
  $$\frac{91	imes 6022	imes 10^{20}}{3041}$$
- step4: Multiply:
  $$\frac{548002	imes 10^{20}}{3041}$$
The number of molecules of CuCNS in the 3.64 g sample is approximately $$1.802 	imes 10^{22}$$ molecules.
The number of molecules of CuCNS in the 3.64 g sample is approximately $$1.802 	imes 10^{22}$$ molecules.

In another set-up, a student has prepared a 3.64 g sample of CuCNS. How
many molecules of CuCNS exist in this sample?
(Avogadro’s constant )

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In another set-up, a student has prepared a 3.64 g sample of CuCNS. How many molecules of CuCNS exist in this sample? (Avogadro’s constant )