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The value of \( x^{p-q} x^{q-r} x^{r-p} \) is equal to \( \begin{array}{ll}\text { a) } x^{p q r} & \text { b) } 0 \\ \text { c) } x & \text { d) } 1\end{array} \)

Ask by French Bob. in India
Feb 03,2025

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Answer

The value of \( x^{p-q} x^{q-r} x^{r-p} \) is \( 1 \).

Solution

To evaluate the expression \( x^{p-q} \cdot x^{q-r} \cdot x^{r-p} \), we can use the properties of exponents: 1. **Multiplication of Like Bases:** When multiplying expressions with the same base, you add the exponents: \[ x^{a} \cdot x^{b} \cdot x^{c} = x^{a+b+c} \] 2. **Applying to the Given Expression:** \[ x^{p-q} \cdot x^{q-r} \cdot x^{r-p} = x^{(p - q) + (q - r) + (r - p)} \] 3. **Simplifying the Exponents:** \[ (p - q) + (q - r) + (r - p) = p - q + q - r + r - p \] Notice that each term cancels out: \[ p - p + q - q + r - r = 0 \] 4. **Final Expression:** \[ x^{0} = 1 \quad \text{(assuming } x \neq 0\text{)} \] **Answer:** \( \boxed{1} \)

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To simplify \( x^{p-q} x^{q-r} x^{r-p} \), we can combine the exponents together. When multiplying bases with the same base, we add the exponents: \[ x^{(p-q) + (q-r) + (r-p)}. \] Now, let's simplify the exponent: \[ (p-q) + (q-r) + (r-p) = p - q + q - r + r - p = 0. \] Thus, we can rewrite the expression as: \[ x^0. \] Since any non-zero number raised to the power of 0 is 1, we conclude that: \[ x^{p-q} x^{q-r} x^{r-p} = 1. \] So, the answer is \( \text{d) } 1 \).

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