Solve for \( x \) \( 8 x+2+3 x+5=x+12 \)

To solve for \( x \) in the equation \( 8x + 2 + 3x + 5 = x + 12 \), first, combine like terms on the left side: 1. Combine the \( x \) terms: \( 8x + 3x = 11x \). 2. Combine the constant terms: \( 2 + 5 = 7 \). So, the equation simplifies to: \[ 11x + 7 = x + 12 \] Next, isolate \( x \) by subtracting \( x \) from both sides: \[ 11x - x + 7 = 12 \] \[ 10x + 7 = 12 \] Now, subtract 7 from both sides: \[ 10x = 12 - 7 \] \[ 10x = 5 \] Finally, divide both sides by 10 to solve for \( x \): \[ x = \frac{5}{10} = \frac{1}{2} \] So, the solution is: \[ x = \frac{1}{2} \]