Question
Find the perimeter of a room which 3.5 m long and 2 m wide. Find the length of a room of perime 20 m and width 3 m .
Ask by Lawson Rose. in Benin
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The perimeter of the first room is 11 meters. The length of the second room is 7 meters.
Solution
Sure, let's solve both problems step by step.
---
### **Problem 1:**
**Find the perimeter of a room that is 3.5 meters long and 2 meters wide.
**Solution:**
The perimeter \( P \) of a rectangular room can be calculated using the formula:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length (\( L \)) = 3.5 meters
- Width (\( W \)) = 2 meters
Plugging the values into the formula:
\[
P = 2 \times (3.5\, \text{m} + 2\, \text{m}) = 2 \times 5.5\, \text{m} = 11\, \text{meters}
\]
**Answer:**
The perimeter of the room is **11 meters**.
---
### **Problem 2:**
**Find the length of a room with a perimeter of 20 meters and a width of 3 meters.
**Solution:**
Again, using the perimeter formula for a rectangle:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Perimeter (\( P \)) = 20 meters
- Width (\( W \)) = 3 meters
Let the length be \( L \). Plugging the known values into the formula:
\[
20 = 2 \times (L + 3)
\]
Divide both sides by 2:
\[
10 = L + 3
\]
Subtract 3 from both sides to solve for \( L \):
\[
L = 10 - 3 = 7\, \text{meters}
\]
**Answer:**
The length of the room is **7 meters**.
---
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Simplify this solution Extra Insights
To find the perimeter of the room with dimensions 3.5 m long and 2 m wide, use the formula for the perimeter of a rectangle, which is P = 2(length + width). Plugging in the values: P = 2(3.5 m + 2 m) = 2(5.5 m) = 11 m. For the second part, we know the perimeter is 20 m and the width is 3 m. Rearranging the perimeter formula gives us length = (perimeter / 2) - width. So length = (20 m / 2) - 3 m = 10 m - 3 m = 7 m. Keep in mind that the dimensions of a room can significantly impact how you arrange furniture or use the space—don’t underestimate the power of measuring! Also, when calculating perimeters, be cautious with units to ensure everything is consistent and accurate.
