Question
\( \left. \begin{array} { l } { \overline { A B } = 16 m } \\ { \overline { C H } = 9 m } \\ { A _ { A B C } = ? } \end{array} \right. \)
Ask by Clark Salinas. in Italy
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
L'area del triangolo \( ABC \) è \( 72 \, m^2 \).
Solution
Per calcolare l'area del triangolo \( ABC \), utilizziamo la formula dell'area di un triangolo:
\[
\text{Area} = \frac{\text{Base} \times \text{Altezza}}{2}
\]
Dove:
- La base \( \overline{AB} = 16 \, m \)
- L'altezza \( \overline{CH} = 9 \, m \)
Sostituendo i valori nella formula:
\[
\text{Area} = \frac{16 \, m \times 9 \, m}{2} = \frac{144 \, m^2}{2} = 72 \, m^2
\]
**Quindi, l'area del triangolo \( ABC \) è \( 72 \, m^2 \).**
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Simplify this solution Mind Expander
To find the area of triangle \( ABC \), we can use the formula for the area \( A \) of a triangle given by the base and height: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, we can consider \( \overline{AB} \) as the base, which is 16 m, and \( \overline{CH} \) as the height, which is 9 m. Now, plug the values into the formula: \[ A = \frac{1}{2} \times 16 \, m \times 9 \, m = \frac{1}{2} \times 144 \, m^2 = 72 \, m^2 \] Thus, the area of triangle \( ABC \) is \( 72 \, m^2 \).
