\( \left. \begin{array} { l } { \overline { A B } = 16 m } \\ { \overline { C H } = 9 m } \\ { A _ { A B C } = ? } \end{array} \right. \)

To find the area of triangle \( ABC \), we can use the formula for the area \( A \) of a triangle given by the base and height: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, we can consider \( \overline{AB} \) as the base, which is 16 m, and \( \overline{CH} \) as the height, which is 9 m. Now, plug the values into the formula: \[ A = \frac{1}{2} \times 16 \, m \times 9 \, m = \frac{1}{2} \times 144 \, m^2 = 72 \, m^2 \] Thus, the area of triangle \( ABC \) is \( 72 \, m^2 \).