Question
upstudy study bank question image url

Condense the expression. \[ \log 6-3 \log \frac{1}{3} \] \( \log [?] \)

Ask by Johnson Christensen. in the United States
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\(\log 162\)

Solution

To condense the expression \(\log 6 - 3 \log \frac{1}{3}\) into the form \(\log [\,?\,]\), follow these steps using logarithm properties: 1. **Apply the Power Rule**: \[ 3 \log \frac{1}{3} = \log \left(\frac{1}{3}\right)^3 = \log \frac{1}{27} \] 2. **Combine the Logarithms**: \[ \log 6 - \log \frac{1}{27} = \log \left(\frac{6}{\frac{1}{27}}\right) = \log (6 \times 27) \] 3. **Simplify the Expression**: \[ 6 \times 27 = 162 \] Therefore, the condensed form of the expression is: \[ \log 162 \] Answer: \(\log 162\)

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Beyond the Answer

To condense the expression \(\log 6 - 3 \log \frac{1}{3}\), we can use the properties of logarithms. Recall that \(a \log b = \log b^a\) and \(\log a - \log b = \log \frac{a}{b}\). First, rewrite \(3 \log \frac{1}{3}\) as \(\log \left(\frac{1}{3}\right)^3\): \[ 3 \log \frac{1}{3} = \log \left(\frac{1}{3}\right)^3 = \log \left(\frac{1}{27}\right). \] Now substitute this back into the original expression: \[ \log 6 - \log \left(\frac{1}{27}\right) = \log \left( \frac{6}{\frac{1}{27}} \right). \] This simplifies to: \[ \log \left( 6 \times 27 \right) = \log 162. \] So, the final condensed expression is: \[ \log[162]. \]

Related Questions

Latest Algebra Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy