Question

Solve each system by elimination. Check your answer. 11. \( \left\{\begin{array}{l}-x+y=-1 \\\ 2 x-y=0\end{array}\right. \)

Ask by Bolton Kelly. in the United States
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The solution is \( x = -1 \) and \( y = -2 \).

Solution

Sure, let's solve the given system of equations by the **elimination method** and then verify the solution. ### Given System: \[ \begin{cases} -x + y = -1 \quad \text{(Equation 1)} \\ 2x - y = 0 \quad \text{(Equation 2)} \end{cases} \] ### Step 1: Add the Equations to Eliminate \( y \) To eliminate \( y \), we'll add **Equation 1** and **Equation 2** together. \[ \begin{align*} (-x + y) + (2x - y) &= -1 + 0 \\ (-x + 2x) + (y - y) &= -1 \\ x + 0 &= -1 \\ x &= -1 \end{align*} \] **Solution for \( x \):** \[ x = -1 \] ### Step 2: Substitute \( x = -1 \) into One of the Original Equations to Find \( y \) Let's substitute \( x = -1 \) into **Equation 2**: \[ 2x - y = 0 \] \[ 2(-1) - y = 0 \\ -2 - y = 0 \\ -y = 2 \\ y = -2 \] **Solution for \( y \):** \[ y = -2 \] ### Solution Set: \[ x = -1 \\ y = -2 \] ### Step 3: **Check** the Solution in Both Equations **Check in Equation 1:** \[ -x + y = -1 \\ -(-1) + (-2) = 1 - 2 = -1 \quad \checkmark \] **Check in Equation 2:** \[ 2x - y = 0 \\ 2(-1) - (-2) = -2 + 2 = 0 \quad \checkmark \] Both equations are satisfied with \( x = -1 \) and \( y = -2 \). ### Final Answer: \[ \boxed{\,x = -1,\quad y = -2\,} \]

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The Deep Dive

To solve the system by elimination, we start with the given equations: 1. \(-x + y = -1\) 2. \(2x - y = 0\) From the first equation, we can express \(y\) in terms of \(x\): \[ y = x - 1. \] Now, substitute this expression for \(y\) into the second equation: \[ 2x - (x - 1) = 0. \] This simplifies to: \[ 2x - x + 1 = 0, \] or \[ x + 1 = 0. \] Thus, \[ x = -1. \] Now, we substitute \(x = -1\) back into the equation for \(y\): \[ y = -1 - 1 = -2. \] The solution to the system is \(x = -1\) and \(y = -2\). So, the solution is \((-1, -2)\). To check our answer, we can substitute \(x\) and \(y\) back into both original equations: First, check the first equation: \[ -(-1) + (-2) = 1 - 2 = -1. \] (Correct!) Next, check the second equation: \[ 2(-1) - (-2) = -2 + 2 = 0. \] (Correct!) Both equations are satisfied, confirming our solution: \( \boxed{(-1, -2)} \).

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