Which subset of \( A \) has a GCF of the elements that is 3 ? A. \( \{9 y, 12 x y\} \) B. \( \{3 x, 15 x, 12 x y\} \) C. \( \{3 x, 9 y, 12 x y, 15 x\} \) D. \( \{5 x y, 15 x, 3 x\} \)
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To find a subset of \( A \) that has a GCF of 3, we need to check the GCF of the elements in each option. For option A, the elements are \( 9y \) and \( 12xy \). The GCF is 3, since 9 and 12 are both divisible by 3 but not by any higher common factor greater than 3. For option B, the elements are \( 3x \), \( 15x \), and \( 12xy \). The GCF here is also 3, because 3, 15, and 12 have 3 as the largest number that divides all of them. For option C, the elements are \( 3x \), \( 9y \), \( 12xy \), and \( 15x \). The GCF is 3 again, as each of these terms includes a factor of 3. For option D, the elements are \( 5xy \), \( 15x \), and \( 3x \). The GCF here is 3, as 15 and 3 both contain 3, but 5xy is not divisible by 3. Therefore, all options have a subset with GCF of 3, but options A, B, and C provide clear sets that meet the criterion specifically.