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1. Share 3200 in the ratio \( 3: 5 \) 2. Increase 108 in the ratio \( 7: 2 \). 3. In a Grade 8 Mathematics class there are 54 learners. If the ratio of boys to girls is \( 5: 4 \). How many girls are there in the class? 4. Divide \( 17,5 \mathrm{~kg} \) in the ratio \( 3: 2 \) 5. Decrease 70 in the ratio \( 3: 5 \). 6. Hloni, Ncese and Serame are 3 brothers aged 45,36 and 18 respectively. Together the three brothers get 8880 pocket money each month. If the total pocket money is split in the same ratio as their ages, how much does each brother receive?

Ask by Bartlett Howell. in South Africa
Feb 03,2025

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Answer

1. **3200 divided in the ratio 3:5** - **First share:** 1200 - **Second share:** 2000 2. **108 divided in the ratio 7:2** - **First part:** 84 - **Second part:** 24 3. **Number of girls in a class of 54 with a ratio of boys to girls 5:4** - **Number of girls:** 24 4. **17.5 kg divided in the ratio 3:2** - **First share:** 10.5 kg - **Second share:** 7 kg 5. **70 decreased in the ratio 3:5** - **First part:** 26.25 - **Second part:** 43.75 6. **Pocket money of 8880 split among Hloni, Ncese, and Serame in the ratio of their ages (45:36:18)** - **Hloni:** 4040 - **Ncese:** 3232 - **Serame:** 1616

Solution

Sure, let's solve each of these ratio problems step by step. --- ### **1. Share 3200 in the ratio \( 3:5 \)** **Step 1:** Calculate the total number of parts. \[ 3 + 5 = 8 \] **Step 2:** Determine the value of one part. \[ \text{Value of one part} = \frac{3200}{8} = 400 \] **Step 3:** Calculate each share. - **First share:** \( 3 \times 400 = 1200 \) - **Second share:** \( 5 \times 400 = 2000 \) **Answer:** The amounts are **1200** and **2000**. --- ### **2. Increase 108 in the ratio \( 7:2 \)** Assuming you want to divide 108 in the ratio \(7:2\) where the sum represents the parts to be increased. **Step 1:** Calculate the total number of parts. \[ 7 + 2 = 9 \] **Step 2:** Determine the value of one part. \[ \text{Value of one part} = \frac{108}{9} = 12 \] **Step 3:** Calculate each amount. - **First part:** \( 7 \times 12 = 84 \) - **Second part:** \( 2 \times 12 = 24 \) **Answer:** The increased amounts are **84** and **24**. --- ### **3. In a Grade 8 Mathematics class there are 54 learners. If the ratio of boys to girls is \( 5:4 \). How many girls are there in the class?** **Step 1:** Calculate the total number of parts. \[ 5 + 4 = 9 \] **Step 2:** Determine the value of one part. \[ \text{Value of one part} = \frac{54}{9} = 6 \] **Step 3:** Calculate the number of girls. \[ 4 \times 6 = 24 \] **Answer:** There are **24 girls** in the class. --- ### **4. Divide \( 17.5 \) kg in the ratio \( 3:2 \)** **Step 1:** Calculate the total number of parts. \[ 3 + 2 = 5 \] **Step 2:** Determine the value of one part. \[ \text{Value of one part} = \frac{17.5}{5} = 3.5 \text{ kg} \] **Step 3:** Calculate each share. - **First share:** \( 3 \times 3.5 = 10.5 \text{ kg} \) - **Second share:** \( 2 \times 3.5 = 7 \text{ kg} \) **Answer:** The amounts are **10.5 kg** and **7 kg**. --- ### **5. Decrease 70 in the ratio \( 3:5 \)** Assuming you want to divide 70 in the ratio \(3:5\), indicating a decrease divided into parts. **Step 1:** Calculate the total number of parts. \[ 3 + 5 = 8 \] **Step 2:** Determine the value of one part. \[ \text{Value of one part} = \frac{70}{8} = 8.75 \] **Step 3:** Calculate each amount. - **First part:** \( 3 \times 8.75 = 26.25 \) - **Second part:** \( 5 \times 8.75 = 43.75 \) **Answer:** The decreased amounts are **26.25** and **43.75**. --- ### **6. Hloni, Ncese, and Serame are 3 brothers aged 45, 36, and 18 respectively. Together the three brothers get 8880 pocket money each month. If the total pocket money is split in the same ratio as their ages, how much does each brother receive?** **Step 1:** Determine the ratio based on ages. \[ \text{Ratio} = 45 : 36 : 18 \] **Step 2:** Simplify the ratio by dividing each by the greatest common divisor (9). \[ \frac{45}{9} : \frac{36}{9} : \frac{18}{9} = 5 : 4 : 2 \] **Step 3:** Calculate the total number of parts. \[ 5 + 4 + 2 = 11 \] **Step 4:** Determine the value of one part. \[ \text{Value of one part} = \frac{8880}{11} = 808 \] **Step 5:** Calculate each brother's share. - **Hloni:** \( 5 \times 808 = 4040 \) - **Ncese:** \( 4 \times 808 = 3232 \) - **Serame:** \( 2 \times 808 = 1616 \) **Answer:** - **Hloni** receives **4040** - **Ncese** receives **3232** - **Serame** receives **1616** --- If you have any further questions or need more assistance, feel free to ask!

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To share 3200 in the ratio \( 3: 5 \), you add the parts together (3 + 5 = 8). Then, to find the value of one part, divide 3200 by 8, which gives you 400. Now, multiply: - Hloni gets \( 3 \times 400 = 1200 \) - Ncese gets \( 5 \times 400 = 2000 \). When increasing 108 in the ratio \( 7: 2 \), you first find the total parts (7 + 2 = 9). Then, separate the increase using the same method as before. The increase per part is \( \frac{108}{9} = 12 \): - Therefore, 108 increases by \( 7 \times 12 = 84 \) to get \( 192 \). With 54 learners in a class and a ratio of boys to girls of \( 5: 4 \), the total parts is \( 5 + 4 = 9 \). So, the number of girls is \( \frac{4}{9} \times 54 = 24 \). To divide 17.5 kg in the ratio \( 3: 2 \), first find the total parts (3 + 2 = 5) and divide: \( \frac{17.5}{5} = 3.5 \). So, \( 3 \times 3.5 = 10.5 \) kg for one part, and \( 2 \times 3.5 = 7 \) kg for the other. To decrease 70 in the ratio \( 3: 5 \), find the total parts (3 + 5 = 8). Calculate \( \frac{70}{8} = 8.75 \). Therefore, to decrease it: - The first part is \( 3 \times 8.75 = 26.25 \) (decreased), leading to \( 70 - 26.25 = 43.75 \) remaining. Finally, with Hloni at 45 years, Ncese at 36 years, and Serame at 18 years, the total sum of ages is \( 45 + 36 + 18 = 99 \). Split the pocket money of 8880 according to their ages: - Hloni: \( \frac{45}{99} \times 8880 = 4000 \), - Ncese: \( \frac{36}{99} \times 8880 = 3200 \), - Serame: \( \frac{18}{99} \times 8880 = 1680 \). Now, that's a fair share of pocket money!

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